Answer:
Answer: a) 15 + 12y b) 14y - 27xy^2 + 18y^3c) 12ar + 54abr - 120brSolution:a) 5x3 + 6x2y15 + 6 x 2y= 15 + 12yb) 7x2y - 27xy^2 + 18y^3=14y - 27xy^2 + 18y^3c) 6a2r + 54arb - 60b2r= 12ar + 54abr - 120br
Step-by-step explanation:
Let
x------> <span>speed on the bicycle
y------> </span><span>speed walking
we know that
</span>x=6+y------> equation 1<span>
speed=distance /time-------> time=distance/speed
1/y=2.5/x-------> y=x/2.5------> x=2.5y-------> equation 2
equals 1 and 2
6+y=2.5y-----> 2.5y-y=6------> 1.5y=6-----> y=6/1.5-----> y=4 mi/h
x=6+y-----> x=6+4-----> x=10 mi/h
the answer is
the speed walking is 4 mi/h
</span><span>
</span>
Answer:
³/5
Step-by-step explanation:
Total = 5 units
Girls = 3 units
~if ⅔ of the girls wear braces
= 2units of girs wear braces
Boys = 2 units
~if ½ of the boys wear braces
= 1unit of boys wear braces
Hence, 2units + 1unit =3 units of the class wears braces.
Total pupils = 5units
total that wear braces out of the whole class = 3/5
If x=mx-3 (which is not clear from your input),
3
then x-mx = -3, or mx-1x = 3, and x(m-1) = 3, and so x = ---------
m-1
