Overall dimensions of the page in order to maximize the printing area is page should be 11 inches wide and 10 inches long .
<u>Step-by-step explanation:</u>
We have , A page should have perimeter of 42 inches. The printing area within the page would be determined by top and bottom margins of 1 inch from each side, and the left and right margins of 1.5 inches from each side. let's assume width of the page be x inches and its length be y inches So,
Perimeter = 42 inches
⇒ 
width of printed area = x-3 & length of printed area = y-2:
area = 

Let's find
:
=
, for area to be maximum
= 0
⇒ 
And ,

∴ Overall dimensions of the page in order to maximize the printing area is page should be 11 inches wide and 10 inches long .
SA=2H(L+W)+LW for open box
20=2H(4+W)+4(W)
distribute
20=8H+2WH+4W
divide both sides by 2
10=4H+WH+2W
solve for 1 variable, pick W
10-4H=WH+2W
10-4H=W(H+2)
(10-4H)/(H+2)=W
V=LWH
subsitute 4 for V, subsitute H for H and (10-4H)/(H+2) for W
V=(4)(H)(10-4H)/(H+2)
V=(40H-16H²)/(H+2)
find max value
take deritivitive of this thing
V'=-16(H²+4H-5)/((H+2)²)
using sign chart
sign changes from positive to negative at H=1
so at H=1
find W
W=(10-4H)/(H+2)
W=2
the dimeionts are
length=4ft
width=2ft
height=1ft
(the volume is 8 cubic feet)
The formula of a slope:

We have the points (2, 5) and (4, 10). Substitute:

This means that 2.5mm of rain falls every hour
Answer:
2k
Step-by-step explanation:
Let k is the ratio between two variables or y = kx
when x double, means: y = k (2x) = 2kx quantity y will change with a ratio 2k