29 times 35 would be 1,015
A^2+b^2=c^2
20^2+b^2=29^2
400+b^2=841
-400. -400
b^2=√441
b=21
First we can find the perimeter of the given rectangle
P=2L+2W (L=length and W=width)
P=2*3+2*4
P=6+8
P=14
So now we want to come up with a different combination of numbers that would give up a perimeter of 14. We know that 14 is divisible by 2 so let's make out width 2. If we plug in 2 as the width and 14 as the perimeters, we can solve for length
14=2L+2*2
14=2L+4
10=2L (subtract 4 from both sides)
L=5
So the dimensions are 5 units and 2 units
Hope this helps!
<u>c.)44 kilometers</u>
Answer:
Solution given:
let
length =L
and
Area =A
Now
we have
Area [A]=1936 square kilometers
now
As we know that
Area of square :length *length
A=l*l
A=l²
Substituting value of A
1936=l²
doing square root on both side

we get
l=
l=2*2*11
l=44 kilometers
So
<u>the length of one side of a </u><u>square</u><u> </u><u>is</u><u> </u><u>4</u><u>4</u><u> </u><u>kilometers</u><u>.</u><u />
Answer: 10, 8, 6 , 4, 2, 0, -2, -4, ...
Explanation: every number of the sequence is the previous less 2 and the first terms is 10.