Question

How many arrangements of three letter can be formed from the letters of the word MATH if anyletter will not be used more than once?

Answer 1

Combinations = n! / (n - r)! r!

$C\text{ = }\frac{n!}{(n-r)!\text{ r!}}\text{ }$

In this case:

n = 4

r = 3

Combinations = 4! /(4-3)! 3! = 24/(1)(6) = 24/6 = 4

Answer:

4 arrangements