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ss7ja [257]
1 year ago
14

How many arrangements of three letter can be formed from the letters of the word MATH if anyletter will not be used more than on

ce?
Mathematics
1 answer:
Mariulka [41]1 year ago
7 0

Combinations = n! / (n - r)! r!

C\text{ = }\frac{n!}{(n-r)!\text{ r!}}\text{ }

In this case:

n = 4

r = 3

Combinations = 4! /(4-3)! 3! = 24/(1)(6) = 24/6 = 4

Answer:

4 arrangements

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The answer to your question is 8*5*4.
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Radda [10]

Remark

Whatever the original price, he gets 70% in the first instance.

He gets 80% in the second instance.

He gets 90% in the third instance

His total income is 240 dollars.

Let the original price be x

Equation

70%x + 80%x +90%x = 240

70% = 0.7 ; 80% = 0.8 ;90% = 0.9

Solution

0.7x + 0.8x + 0.9x = 240 Take out x as a common factor and add the decimals.

x (0.7 + 0.8 + 0.9) = 240

2.4x = 240 Divide both sides by 2.4

x = 240/2.4

x = 100

So the watches should have brought in 3*100 = 300 dollars.

He only brought in 240 dollars.

He lost 300 - 240 = 60 dollars.

The answer is B.

7 0
2 years ago
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