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1 year ago

What mass of oxygen is needed to burn 4g of hydrogen, given the equation below

Chemistry

1 answer:

aleksandrvk [35]1 year ago

7 0

32g of oxygen is required to burn 4g of hydrogen.

Define molecular mass.

A specific molecule's mass is expressed in daltons and is known as the molecular mass (m) (Da or u). Due to the varying isotopes of an element that they contain, multiple molecules of the same substance can have distinct molecular weights.

The total atomic mass of every atom in a molecule, calculated using a scale with hydrogen, carbon, nitrogen, and oxygen having atomic masses of 1, 12, 14, and 16, respectively. For instance, water has a molecular mass of 18 (2 + 16), which consists of two hydrogen atoms and one oxygen atom. known also as molecular weight.

In ,2H2+O2-----> 2H2O

H 2 molecules have a mass of 2 g/mol.

The molecular weight of oxygen is 32 g/mol.

When the chemical equation is balanced,

To totally react, 32 g of oxygen are needed for every 22=4 g of hydrogen.

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When nad becomes nadh, it is being? oxidized and releasing chemical energy. reduced and gaining chemical energy. oxidized and ga

3241004551 [841]

When NAD becomes NADH, it is being reduced and gaining chemical energy.

Nicotinamide adenine dinucleotide (NAD), a coenzyme, can exist in two forms, NAD⁺ (oxidized) and NADH (reduced form).

Electrons and protons released in catabolism reactions are attached to NAD⁺. The conversion of NAD⁺ to NADH is important reaction for production of ATP during the cellular respiration.

Reduction is lowering oxidation number because element, ion or compound gain electrons.

Chemical equation for reaction of reduction of NAD⁺ (see picture below):

NAD⁺ + 2e⁻ + H⁺ → NADH

Nicotinamide adenine dinucleotide (NAD) is made of two nucleosides joined by pyrophosphate.

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8 0

1 year ago

The standard enthalpy change for the following reaction is 232 kJ at 298 K. 2 H2CO(g) 2 C(s,graphite) + 2 H2(g) + O2(g) ΔH° = 23

Georgia [21]

Answer: The standard enthalpy change for this reaction is -116 kJ

Explanation:

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

The given chemical reaction is,

$2H_2CO(g)\rightarrow 2C(s, graphite)+2H_2(g)+O_2(g)$

$\Delta H^0=232KJ$

Now we have to determine the value of $\Delta H$ for the following reaction i.e,

$)C(s, graphite)+H_2(g)+\frac{1}{2}O_2(g)\rightarrow H_2CO(g)$ $\Delta H^0'=?$

According to the Hess’s law, if we reverse the reaction then the $\Delta H$ will change its sign and if we half the reaction, then the

So, the value $\Delta H^0'$ for the reaction will be:

$\Delta H^0'=\frac{(-232kJ/mole)}{2}=-116kJ$

Hence, the standard enthalpy change for this reaction is -116 kJ

7 0

4 years ago

A chemist measures the energy change Delta H during the following

Ann [662]

Answer: 1) endothernic

2) Yes absorbed

Explanation:

Decomposition is a chemical reaction in which one reactant gives two or more than two products. All decomposition reactions are endothermic reactions as energy is absorbed to break the bonds.

Endothermic reactions are defined as the reactions in which energy of the product is greater than the energy of the reactants. The total energy is absorbed in the form of heat and $\Delta H$ for the reaction comes out to be positive.

Exothermic reactions are defined as the reactions in which energy of the product is lesser than the energy of the reactants. The total energy is released in the form of heat and $\Delta H$ for the reaction comes out to be negative.

5 0

3 years ago

What does animals exhale?

Mademuasel [1]

Answer:

Carbon dioxide

Explanation:

Humans are animals and we exhale carbon dioxide

6 0

3 years ago

Read 2 more answers

The reaction described in part a required 3.77 l of magnesium chloride. what is the concentration of this magnesium chloride sol

katrin [286]

Assuming you are talking about the atomic mass of magnesium chloride
M = n/V
M = 1/3.77
M = .265

6 0

3 years ago