As atomic number increases atomic radii also increase down group 1. ionisation energy down group 1 will also decrease because as atomic radii gets bigger there is less electrostatic force between nuclei and electrons so less energy needed to remove valence electron.
You might need to take more pictures so we can see all the equations clearly
Hey, lovely! It's a pretty lengthy process but here is a pretty clear video on how to do it. Hope this helps ya!
https://www.khanacademy.org/science/chemistry/chemical-reactions-stoichiome/balancing-chemical-equat...
Answer:
1. A state of balance in which the rates of the forward and reverse reactions are equal.
Explanation:
A dynamic equilibrium is like a cycle, the reactants change to products, but the products also change to reactants keeping the amount of each constant.
2. A state of balance in which the forward reaction stops but reverse reaction continues.
In this statement there isnt a equilibrium. The products will change to reactants until the reaction stops.
3. A state of balance in which the forward reaction continues but reverse reaction stops.
Here the reactants will change to products until the reaction stops.
4. A state of balance in which the forward and reverse reactions stop.
In this case the reaction has stopped.
We are given the base dissociation constant, Kb, for Pyridine (C5H5N) which is 1.4x10^-9. The acid dissociation constant, Ka for the Pyridium ion or the conjugate acid of Pyridine is to be determined. We know from our chemistry classes that:
Kw = Kb * Ka
where Kw is always equal to 1x10^-14
so, to solve for Ka of Pyridium ion, substitute Kb to the equation together with Kw and solve for Ka:
1x10^-14 = 1.4x10^-9 * Ka
solve for Ka
Ka = 7.14x10^-6
Therefore, the acid dissociation constant of Pyridinium ion is 7.14x10^-6.
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