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ExtremeBDS [4]
1 year ago
6

Helppppsolve for X and then find the measure of

Mathematics
1 answer:
miskamm [114]1 year ago
6 0

Here in this question, we are to solve for x and get the measure of Angle A

Mathematically,

∠A = ∠B

The reason for this is because both are corresponding angles and corresponding angles are equal.

Since they are equal in value, we can equate the given expressions for each of the two angles

Thus;

7x + 40 = 3x + 112

Let us collect like terms

7x-3x = 112 - 40

4x = 72

x = 72/4

x = 18

But the question asks to get the value of ∠A

From the questionn, we are told that ∠A = 7x + 40

To get the value of ∠A, we need to substitute x

∠A = 7(18) + 40

∠A = 126 + 40

∠A = 166

∠A = 166 and x = 18

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\angle\text{VUR}=\angle\text{QRU}=134º

5 0
1 year ago
Please can u answer these for me
ziro4ka [17]
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4 0
3 years ago
How do you write -1.838383
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6 0
4 years ago
Which expression is equivalent to √48x5, if x> 0?
Lerok [7]

Answer:

C. 4x²√(3x)

Step-by-step explanation:

if x > 0

\sqrt{48x^{5}} =\sqrt{48} \times \sqrt{x^{5}}

          =\sqrt{16\times 3} \times \sqrt{x^{4}\times x}

          =\sqrt{16} \times \sqrt{3} \times \sqrt{x^{4}} \times \sqrt{x}

          =4\times \sqrt{3} \times \sqrt{\left( x^{2}\right)^{2}  } \times \sqrt{x}

          =4\times \sqrt{3} \times x^{2}\times \sqrt{x}

          =4\times x^{2} \times  \sqrt{3} \times \sqrt{x}

          =4\times x^{2}\times \sqrt{3x}

8 0
2 years ago
The figure shows a kite inside a rectangle. Which expression represents the area of the shaded region? 2x2 4x2 6x2 8x2
Savatey [412]
The picture in the attached figure

we know that
area of the <span>the shaded region=area of rectangle -area of a kite

area of rectangle=(3x+x)*(x+x)----> 4x*2x---> 8x</span>²

area of a kite=(1/2)*[d1*d2]
where d1 and d2 are the diagonals
d1=4x
d2=2x
so
area of a kite=(1/2)*[4x*2x]----> 4x²

area of the the shaded region=8x²-4x²-----> 4x²

the answer is 
4x²

4 0
3 years ago
Read 2 more answers
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