<span>First of all to calculate the distance between two points we can use distance formula
d=Square Root [(x2-x1)^2 + (y2-y1)^2]
Now substitute the given points p(x1,y1) and q(x2,y2)in above distance formula
The values are X2=3, X1=8and Y2=8and Y1=2.
After Substituting the values
d=Square Root[(-5)^2+(6)^2]
d=Square Root(25+36]
d=Square Root[61]
d=7.8
7.8 is the distance between points P(8, 2) and Q(3, 8) to the nearest tenth.</span>
Yes because 9+4 = 13 and if you plug in the y and x it turns out true
The width of the insect is 0.17 cm and the height of the insect is 0.125 cm.
Step-by-step explanation:
Step 1:
The scale factor is given by dividing the measurement after scaling by the same measurement
The given drawing of the insect is larger than the actual insect.
The scale factor is 20: 1 which means 20 cm on the drawing is 1 cm on the actual insect.
Step 2:
To obtain the actual insect's dimensions, we divide the dimensions of the drawing by 20.
The width of the actual insect 
The height of the actual insect 
The width of the insect is 0.17 cm and the height of the insect is 0.125 cm.
Write several instances of the ratio,then plot the ratios as points on the graph
Answer:
3 hours
Step-by-step explanation:
To find the number of hours the plumber was at the house, we need to solve for x.
22x + 50 = 116
22x = 116 - 50
22x = 66
22x/22 = 66/22
x = 3
