Sum of n terms of a geometric series is
Sn = a1 (r^n-1)/(r-1)
a1 = 1st term = 4
r = common ratio = 12/4 = 3
so, the sum is
Sn = 4 (3^n-1)/(3-1) = 2(3^n-1)
8x51. 8x50=? 8x5=40. 40 x 10 = 400 8x50=400. 8x1=8 400+8=408.
Answer:
22
Step-by-step explanation:
x-1 is a midsegment.
According to the Triangle midsegment theorem, x-1 is half of the third side (42)
x-1 = 42/2
x-1 = 21
x= 22
or
2x-2=42
2x=44
x=22
Hope this helps!
The common difference, d, is 5 and the starting value, a, is 2.
Filling this in the form of

<span>you get
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This should help 10-1=9 9÷3=3 x=3