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The distances between three cities on a map are 45 miles, 56 miles, and 72 miles. Do the positions of

ollegr [7]

Answer:

The position of the three cities do not form a right-triangle.

Step-by-step explanation:

There are three cities on a map (say A, B, and C).

Now, the distances between them are 45 miles, 56 miles, and 72 miles.

i.e. AB= 45 miles, BC= 56 miles and CA =72 miles.

If the three cities A, B, C form a right-angled triangle on the map, then applying Pythagoras Theorem AB² +BC² =AC²

or, AC= √(AB² +BC²) must be satisfied.

Now, right-hand side of the above equation =√(45²+56²) =71.84 ≠ 72 (AC)

Hence, Right-hand side ≠ Left-hand side.

Therefore, the positions of the three cities do not form a right triangle. (Answer)

6 0

3 years ago

Regular hexagon ABCDEF has vertices at A(4, 4!3), B(8, 4!3), C(10, 2!3), D(8, 0), E(4, 0) and F(2, 2!3).

marissa [1.9K]

Since the given hexagon is a regular hexagon all it's sides will be of equal length. Now, we know that the Area of any regular hexagon is given by:

$A=\frac{3\sqrt{3}}{2} a^2$

Where $A$ is the area of the regular hexagon

$a$ is the side length of the regular hexagon

Also, it's Perimeter is given by:

$P=6a$

Thus, all that we need to do is to find the side length of any one of the sides and to do that let us have a look at at the data of vertices points given and find out which points are definitely adjacent to each other and are also easy to calculate.

A quick search will yield that D(8, 0) and E(4, 0) are definitely adjacent to each other.

Please check the attached file here for a better understanding of the diagram of the original regular hexagon. Points D and E indeed are adjacent to each other.

Let us now find the distance between the points D and E using the distance formula which is as:

$d=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}$

Where $d$ is the distance.

$(x_1,y_1)$ and $(x_2,y_2)$ are the coordinates of points D and E respectively. (please note that interchanging the values of the coordinates will not alter the distance $d$ )