All categories

3 years ago

Point C ∈ AB and AB=18 cm. The distance from C to A is 3 cm. shorter than the distance from C to B. Find AC and CB.

Mathematics

1 answer:

gogolik [260]3 years ago

7 0

Answer:

AC=7.5 cm

CB=10.5cm

Step-by-step explanation:

Since we don't know the distance from C to B, we can label it as x. Our equation will be x+(x-3)=18. Simplify that so it is 2x-3=18. Add 3 to both sides and get 2x=21. x=10.5 So AC=7.5 cm and CB is 10.5 cm

You might be interested in

Vector A has a magnitude of 2.00 m and vector B has a magnitude of 5.00 m. If the direction of each vector is unknown, what is t

aliina [53]

C it look and is more right than the others

6 0

3 years ago

The edge of a cube is 4 inches. The area of a cross section perpendicular to one face is ___square inches, and its perimeter is_

diamong [38]

Try 8 and 12.......................................

3 0

3 years ago

Read 2 more answers

Solve pls brainliest

kakasveta [241]

Answer:

20/25

Step-by-step explanation:

divide the denominators

25/5=5

multiply the numerator

4*5=20

6 0

2 years ago

14.

ddd [48]

Answer: Yes the win level is greater than 1/2

Step-by-step explanation: 32/52 is greater than 1/2

8 0

3 years ago

Circle B has a center at point (0, 2) and a point W on the circle at (3, 3). Which equation represents a line that is tangent to

Solnce55 [7]

According to the given information, the equation represents a line that is tangent to the circle and goes through the point W is given by:

y = -x + 6.

<h3>What is the equation of the circle?</h3>

The equation of a circle of center $(x_0,y_0)$ and radius r is given by:

$(x - x_0)^2 + (y - y_0)^2 = r^2$

In this problem, we have that the center is at point (0,2), hence:

$x^2 + (y - 2)^2 = r^2$

It goes through point (3,3), hence:

$3^2 + (3 - 2)^2 = r^2$

$r^2 = 10$

Hence, the equation is:

$x^2 + (y - 2)^2 = 10$

<h3>What is the equation of the tangent line at point W?</h3>

It is given by:

$y - y(0) = \frac{dy}{dx}|_{W}(x - x(0))$

Applying implicit differentiation, we have that:

$2x + 2y\frac{dy}{dy} = 0$

$\frac{dy}{dx} = -\frac{x}{y}$

Point W(3,3), hence:

$(x_0, y_0) = (3,3)$

$\frac{dy}{dx} = -\frac{3}{3} = -1$

Hence the equation is:

y - 3 = -(x - 3).

y = -x + 6.

More can be learned about the equation of a tangent line at brainly.com/question/8174665

5 0

3 years ago