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Leno4ka [110]
1 year ago
12

According to a survey, 62% of americans go on vacation each . two americans are chosen from a group of 100 americans. what is th

e probability that one or both of the people chosen does not go on vacation each ?
Mathematics
1 answer:
Drupady [299]1 year ago
6 0

probability of one go on vacation and one does not go on vacation is 0.2356 and probability none of them go on vacation is 0.1444

According to a survey, 62% of americans go on vacation each .

two americans are chosen from a group of 100 americans.

what is the probability that one or both of the people chosen does not go on vacation each ?

62% americans go on vacation t

hen 38% americans does not go on vacation

Total group of americans is 100

out of 100 americans 62 go on vacation and 38 does not go on vacation

probability of one go on vacation and one does not go on vacation

= 0.62*0.38

=0.2356

probability none of them go on vacation

= 0.38*0.38

=0.1444

learn more about of probability here

brainly.com/question/11234923

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