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vesna_86 [32]
1 year ago
15

Name the postulate or theorem that proves each pair of triangles similar. Explain your reasoning.

Mathematics
1 answer:
yanalaym [24]1 year ago
8 0

The postulate or theorem that proves each pair of triangles similar is Side-Angle-Side similarity theorem.

\begin{gathered} \text{Tan }\angle M=\frac{15}{21}=\frac{5}{7} \\ \text{Tan }\angle L=\frac{15+5}{28}=\frac{20}{28}=\frac{5}{7} \end{gathered}

Since angle M and angle L are acute, then

\angle M\cong\angle L

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54 - a = 12 i believe
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How do i solve this question
Ludmilka [50]

Answer:

a\frac{c}{8\pi  b}

Step-by-step explanation:

Divide both sides by 8\pi b

\frac{8\pi ab}{8\pi b} =\frac{c}{8\pi b}

Simplify:

a\frac{c}{8\pi  b} ; a\frac{c}{8\pi  b}; b\neq 0

8 0
3 years ago
Can someone check if my answer is correct? Thank you!
a_sh-v [17]

Answer:

Step-by-step explanation:

you are correct.

3 0
3 years ago
What compound inequality describes the graph shown below?
NARA [144]
Answer is less than or equal to -7 or -5greater than or equal to

4 0
3 years ago
Hello there!
otez555 [7]

Answer:

24  Domain: s>=2  or s<=-2

25. 3x^2 +14x +10

26. x^2 -2x+5  

Step-by-step explanation:

24.  Domain is the input or s values

square roots must be greater than or equal to zero

s^2-4 >=0

Add 4 to each side

s^2 >=4

Take the square root

s>=2  or s<=-2


25.  f(g(x))  stick g(x) into f(u) every place you see a u

f(u) = 3u^2 +2u-6

g(x) = x+2

f(g(x) = 3(x+2)^2 +2(x+2) -6

Foil the squared term

       = 3(x^2 +4x+4) +2x+4-6

Distribute

       = 3x^2 +12x+12 +2x+4-6

Combine like terms

   =3x^2 +14x +10


26 f(g(x))  stick g(x) into f(u) every place you see a u

f(u) = u^2+4

g(x) = x-1

f(g(x) = (x-1)^2 +4

Foil the squared term

         = (x^2 -2x+1) +4

         = x^2 -2x+5  

7 0
3 years ago
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