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1 year ago

Please please help! :)

Mathematics

1 answer:

weqwewe [10]1 year ago

8 0

Answer:

∠ 2 = 140°

Step-by-step explanation:

the left base angle in the triangle and 110° are a linear pair and sum to 180°

base angle + 110° = 180° ( subtract 110° from both sides )

base angle = 70°

the 2 sides of the triangle are congruent so Δ is isosceles with base angles congruent.

the vertex of the Δ is then

(180 - 70 - 70)° = 180° - 140° = 40°

the vertex and ∠ 2 are a linear pair and sum to 180° , that is

∠ 2 + 40° = 180° ( subtract 40° from both sides )

∠ 2 = 140°

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Question 7: Solve this system A.(15, 10) B.(-15, 10) C.(-10, 25) D.(10, 15)

Alexandra [31]

Answer:

D. (10, 15)

Step-by-step explanation:

Hi there!

We are given the following system:

$\frac{1}{2}x$ +y=20

x+4y=70

And we want to solve it (find the values of x and y).

Let's use substitution for this problem, where we will isolate one variable on one side, while the other side contains an expression with the other variable. Then, we use the expression to solve for the variable that the expression contains, then use the value of that variable to solve for the aforementioned isolated variable.

Subtract $\frac{1}{2}x$ from both sides in the first equation

y=20- $\frac{1}{2}x$

Now substitute 20- $\frac{1}{2}x$ as y in x+4y=70

x+4(20- $\frac{1}{2}x$ )=70

Do the distributive property

x+80-2x=70

Combine like terms on the left

-x+80=70

Subtract 80 from both sides

-x=-10

Multiply both sides by -1

x=10

We found the value of x. Now let's use that value to find what y is

Since we know that y=20- $\frac{1}{2}x$ and x=10, we can substitute 10 as the value of x to solve for y

In that case,

y=20- $\frac{1}{2}$ (10)

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y=15

The answer is x=10, y=15, or as a point, (10, 15), aka D

Hope this helps!

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2 years ago

1 point

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Step-by-step explanation:

Given that;

If V₁ ....... V₄ are in R⁴ and V₃ = 2V₁ + V₂ then {V₁, V₂, V₃, V₄} is linearly dependent.

Lets {V₁, V₂, V₃, V₄} are linearly dependent

Then there exist a scalars C₁, C₂, C₃, C₄

So that C₁V₁ + C₂V₂ + C₃V₃ + C₄V₄ = 0

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therefore option B id the right answer.

- True. The vector V₃ is a linear combination of V₁ and V₂, so at least one of the vectors in the set is a linear combination of the others and set is linearly dependent.

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