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salantis [7]
3 years ago
13

What is the answer and how do I solve it?

Mathematics
1 answer:
vichka [17]3 years ago
4 0
The lengths of the rectangles are 7 and 12 respectively.  Form the ratio 7/12.  The widths of the rects. are x and 5 respectively.  Form the ratio x/5.  Now equate these two ratios:

7       x
--- = ---
12     5

Solve this for x.  One way to do this would be to cross-multiply, obtaining 12x = 35, and solving this result for x.  x will be a fraction.  Write the numerator and denominator in the boxes given.
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F(x) = 17 - 2x<br> Find f(a + 7)
Fudgin [204]

Answer:

-2a + 3

Step-by-step explanation:

We can substitute a + 7 for x:

f(a + 7) = 17 - 2(a+7) = 17 - 2a - 14 = -2a + 3

4 0
3 years ago
A) Simplify the expression and explain each step
Arte-miy333 [17]
4x3x = 12x
4x2 = 8
So 12x+8-2

3 0
3 years ago
In onenote show how many positive integers less than 50 are multiples of 4, but not multiples of 6
dimaraw [331]
Multiples of 4 = 4 8 12 16 20 24 28 32 36 40 44 48

After Removing multiples of 6= 4 8 16 20 28 32 40 44
5 0
3 years ago
Triangle XYZ is shown, where n ≥ 5. Triangle X Y Z is shown. The length of side X Y is n + 4, the length of side Y Z is 2 n, and
motikmotik

Answer:

The longest side of the triangle is YZ, the shortest side is ZX, the largest angle is ∠X and the smallest angle is ∠Y.

Step-by-step explanation:

The lengths of the sides of the triangle XYZ are as follows:

XY = n + 4

YZ = 2n

ZX = n - 2

According to the triangle inequality theorem, the sum of two sides of a triangle is always greater than the third side.

Then,

XY < YZ + ZX ⇒ n + 4 < 2n + n - 2 ⇒ n + 4 < 3n - 2 ⇒ 2n > 6 ⇒ n > 3

YZ < XY + ZX ⇒ 2n < n + 4 + n - 2 ⇒ 2n < 2n + 2 ⇒ 0 < 2

ZX < XY + YZ ⇒ n - 2 < n + 4 + 2n ⇒ n - 2 < 3n + 4 ⇒ 2n > -6 ⇒ n > -3

It is provided that <em>n</em> ≥ 5.

Then the sides of the triangle are:

XY = n + 4 ≥ 5 + 4 = 9

YZ = 2n ≥ 2 × 5 = 10

ZX = n - 2 ≥ 5 - 2 = 3

So, the longest side of the triangle is YZ. And the shortest side is ZX.

The largest angle of a triangle is opposite to the longest side.

The angle opposite to YZ would be X. So, the largest angle is ∠X.

The smallest angle of a triangle is opposite to the shortest side.

The angle opposite to ZX would be Y. So, the smallest angle is ∠Y.

Thus, the longest side of the triangle is YZ, the shortest side is ZX, the largest angle is ∠X and the smallest angle is ∠Y.

6 0
3 years ago
Quadrilateral ABCD has the following vertices.
Marizza181 [45]
A(-5,5)
B(4,5)
C(2,0)
D(-5,-2)

AB,BC,CD,DA

AB = [4-(-5)),5-5]=[9,0]
Lenght  AB= \sqrt{9^2+0^2}= \sqrt{81}  =9

BC = [2-4,0-5]=[-2,-5]
Lenght  BC=\sqrt{(-2)^2+(-5)^2}=\sqrt{4+25}=\sqrt{29}

CD = [-5-2,-2-0]=[-7,-2]
Lenght  CD=\sqrt{(-7)^2+(-2)^2}=\sqrt{49+4}=\sqrt{53}

DA =[-5-(-5),-2-5]=[0,-7]
Lenght DA=\sqrt{0^2+(-7)^2}=\sqrt{49}=7

sorted from longest to shortest:
AB, CD,DA,BC
\sqrt{81}, \sqrt{53}, \sqrt{49}, \sqrt{29}

3 0
3 years ago
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