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Arturiano [62]
1 year ago
7

A shopkeeper bought 775 kg of wheat . He wants to divide all the wheat into 8 bags of the same size. How much Wheat Can he store

in 1 bag? How much will be left?
Mathematics
1 answer:
Arturiano [62]1 year ago
6 0

In order to calculate how much wheat will be stored in each bag, let's divide the total amount of wheat by the number of bags:

\frac{775}{8}=96.875

Assuming that the amount of wheat each bag can hold is a whole number, so each bag can hold 96 kg (otherwise, each bag would hold 96.875 kg and there would be no wheat left).

Then, to find how much wheat will be left, let's calculate how much the 8 bags will hold, and then we subtract this value from the total:

\begin{gathered} 96\cdot8=768 \\  \\ 775-768=7 \end{gathered}

So there will be 7 kg left.

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3x+y=4 <br> x+2y=-2<br> what is the answer
Taya2010 [7]

Answer:

2(3x+y=4)

1(x+2y=-2)

6x+2y=8

<u>(-) x+2y=-2</u>

<u>5x=10</u>

5

x=2

x+2y=-1

2+2y=-1

<u>-</u><u>2</u><u> -</u><u>2</u>

<u>2y=-</u><u>3</u>

2

y=-3/2

Step-by-step explanation:

  1. multiply the first equation by 2 to make y equal to each other.
  2. subtract to eliminate y
  3. divide by 5 to get x
  4. take one of the equations
  5. replace x by 2 to solve for y
3 0
3 years ago
angle A and angle B are complementary angles. If m angle A = (x-16)degrees and m angle B = (3x+28)degrees, then find the measure
Ahat [919]

Answer:

4x \times 448

Step-by-step explanation:

A=

a = (x - 16)

b = (3x + 28)

So you add :

x \: and3x

To get

4x

Then you do :

16 \times 28

To get :

448

Answer is :

4x \times 448

4 0
3 years ago
Health insurance benefits vary by the size of the company (the Henry J. Kaiser Family Foundation website, June 23, 2016). The sa
xxMikexx [17]

Answer:

\chi^2 = \frac{(32-42)^2}{42}+\frac{(18-8)^2}{8}+\frac{(68-63)^2}{63}+\frac{(7-12)^2}{12}+\frac{(89-84)^2}{84}+\frac{(11-16)^2}{16}=19.221

Now we can calculate the degrees of freedom for the statistic given by:

df=(rows-1)(cols-1)=(3-1)(2-1)=2

And we can calculate the p value given by:

p_v = P(\chi^2_{2} >19.221)=0.000067

And we can find the p value using the following excel code:

"=1-CHISQ.DIST(19.221,2,TRUE)"

Since the p values is higher than a significance level for example \alpha=0.05, we can reject the null hypothesis at 5% of significance, and we can conclude that the two variables are dependent at 5% of significance.

Step-by-step explanation:

Previous concepts

A chi-square goodness of fit test "determines if a sample data matches a population".

A chi-square test for independence "compares two variables in a contingency table to see if they are related. In a more general sense, it tests to see whether distributions of categorical variables differ from each another".

Solution to the problem

Assume the following dataset:

Size Company/ Heal. Ins.   Yes   No  Total

Small                                      32   18    50

Medium                                 68     7    75

Large                                     89    11    100

_____________________________________

Total                                     189    36   225

We need to conduct a chi square test in order to check the following hypothesis:

H0: independence between heath insurance coverage and size of the company

H1:  NO independence between heath insurance coverage and size of the company

The statistic to check the hypothesis is given by:

\sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}

The table given represent the observed values, we just need to calculate the expected values with the following formula E_i = \frac{total col * total row}{grand total}

And the calculations are given by:

E_{1} =\frac{50*189}{225}=42

E_{2} =\frac{50*36}{225}=8

E_{3} =\frac{75*189}{225}=63

E_{4} =\frac{75*36}{225}=12

E_{5} =\frac{100*189}{225}=84

E_{6} =\frac{100*36}{225}=16

And the expected values are given by:

Size Company/ Heal. Ins.   Yes   No  Total

Small                                      42    8    50

Medium                                 63     12    75

Large                                     84    16    100

_____________________________________

Total                                     189    36   225

And now we can calculate the statistic:

\chi^2 = \frac{(32-42)^2}{42}+\frac{(18-8)^2}{8}+\frac{(68-63)^2}{63}+\frac{(7-12)^2}{12}+\frac{(89-84)^2}{84}+\frac{(11-16)^2}{16}=19.221

Now we can calculate the degrees of freedom for the statistic given by:

df=(rows-1)(cols-1)=(3-1)(2-1)=2

And we can calculate the p value given by:

p_v = P(\chi^2_{2} >19.221)=0.000067

And we can find the p value using the following excel code:

"=1-CHISQ.DIST(19.221,2,TRUE)"

Since the p values is higher than a significance level for example \alpha=0.05, we can reject the null hypothesis at 5% of significance, and we can conclude that the two variables are dependent at 5% of significance.

3 0
3 years ago
Which equation represents line shown in the accompanying<br> diagram?
Sergeu [11.5K]
I am pretty sure it’s c because you go up 4 and over 3 to the right so that would be plus 3
5 0
3 years ago
07.03 LC)
Inga [223]
Q1.\\p\%=\dfrac{p}{100};\ 20\%=\dfrac{20}{100}=0.20=0.2\\\\20\%-French\ of\ 500\ people\\\\0.2\cdot500=100\leftarrow Answer


Q2.\\\dfrac{white}{all}\cdot\dfrac{yellow}{all-1}\\\\7+8+9=24-number\ of\ all\ roses\\\\\dfrac{9}{24}\cdot\dfrac{8}{24-1}=\dfrac{9}{24}\cdot\dfrac{8}{23}=\dfrac{72}{552}\leftarrow Answer


Q3.\\5-number\ of\ 2\\100-number\ of\ all\\\\\dfrac{5}{100}\leftarrow Answer


Q4.\\1+5+10=16-number\ of\ all\ marbles\\\\\dfrac{10}{16}\cdot\dfrac{10-1}{16-1}=\dfrac{10}{16}\cdot\dfrac{9}{15}\leftarrow Answer
4 0
3 years ago
Read 2 more answers
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