Leann is 3 cm taller than Fred. If Fred's height is f cm, then Leann's height is cm?

Factorise completely<br> 12x4yz2−8x3y3z2

Lina20 [59]

Final result :

4x3yz2 • (3x - 2y2)
Reformatting the input :

Changes made to your input should not affect the solution:

(1): "z2" was replaced by "z^2". 4 more similar replacement(s).

Step by step solution :

Step 1 :

Equation at the end of step 1 :

(((12•(x4))•y)•(z2))-((23x3•y3)•z2)
Step 2 :

Equation at the end of step 2 :

(((22•3x4) • y) • z2) - 23x3y3z2

8 0

2 years ago

100 POINTS IF U GET THIS RIGHT!

ANTONII [103]

$\begin{gathered}\\ \sf\longmapsto Area\:of\:rectangle=Length×Breadth\end{gathered}$

Length= 13.8 ft
Breadth= 11.9 ft

$\begin{gathered}\\ \sf\longmapsto Area=13.8×11.9\end{gathered}$

$\begin{gathered}\\ \sf\longmapsto ⚘Area=164.22ft^{2}\end{gathered}$

3 0

2 years ago

Read 2 more answers

Evaluate $\dfrac{2\sqrt{72}}{\sqrt{8}+\sqrt{2}}$.

Pavlova-9 [17]

<h3>Answer: 4</h3>

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Work Shown:

$\frac{2\sqrt{72}}{\sqrt{8}+\sqrt{2}}\\\\\frac{2\sqrt{36*2}}{\sqrt{4*2}+\sqrt{2}}\\\\\frac{2\sqrt{36}*\sqrt{2}}{\sqrt{4}*\sqrt{2}+\sqrt{2}}\\\\\frac{2*6*\sqrt{2}}{2*\sqrt{2}+\sqrt{2}}\\\\\frac{12\sqrt{2}}{2\sqrt{2}+\sqrt{2}}\\\\\frac{12\sqrt{2}}{3\sqrt{2}}\\\\\frac{12}{3}\\\\4$

Note in step 2, I factored each number in the square root to pull out the largest perfect square factor. From there, I used the rule that $\sqrt{A*B} = \sqrt{A}*\sqrt{B}$ to break up the roots.