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djyliett [7]
1 year ago
9

Events A and B are mutually exclusive. Suppose event A occurs with probability 0.23 and event B occurs with probability 0.21.

Mathematics
1 answer:
evablogger [386]1 year ago
3 0

Using it's concept, the probabilities for this problem are given as follows:

a) A occurs and B does not: 0.1817 = 18.17%.

b) Either occurs: 0.3434 = 34.34%.

<h3>What is a probability?</h3>

A probability is calculated as the <u>number of desired outcomes in the experiment divided by the number of total outcomes in the experiment</u>.

In the context of this problem, we have two mutually exclusive events, meaning that they cannot happen together.

For item a, we have that:

  • The probability of A occurring is 0.23.
  • The probability of B not occurring is of 1 - 0.21 = 0.79.

The events are mutually exclusive, hence we can multiply the probabilities as follows:

p = 0.23 x 0.79 = 0.1817 = 18.17%.

For item b, we add the probability in item with the probability of B occurring and A not, found as follows:

  • The probability of B occurring is 0.21.
  • The probability of A not occurring is of 1 - 0.23 = 0.77.

Hence:

p = 0.1817 + 0.21 x 0.77 = 0.3434 = 34.34%.

More can be learned about probabilities at brainly.com/question/14398287

#SPJ1

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