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irina1246 [14]
3 years ago
14

The distribution of total body protein in healthy adult men is approximately Normal with mean 12.3 kg and standard deviation 0.1

kg. Reference: Ref 13-9 If you take a random sample of 25 healthy adult men, what is the probability that their average total body protein is between 12.25 and 12.35 kg? Select one: a. 0.9876 b. 0.3829 c. 0.0796 d. 0.0062
Mathematics
1 answer:
Gelneren [198K]3 years ago
4 0

Answer: a. 0.9876

Step-by-step explanation:

Given : The distribution of total body protein in healthy adult men is approximately Normal with mean 12.3 kg and standard deviation 0.1 kg.

\mu=12.3 and \sigma=0.1

sample size : n= 25

Let x denotes the  total body protein in healthy adult men in the sample.

Then, the probability that their average total body protein is between 12.25 and 12.35 kg will be :-

P(12.25

∴ The correct answer is a. 0.9876

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Answer:

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So for this case we have more variation for the data of systolic on left compared to the data systolic on right but the difference is not big since 0.170-0.147 = 0.023.

Step-by-step explanation:

Assuming the following data:

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The coefficient of variation is defined as " a statistical measure of the dispersion of data points in a data series around the mean" and is defined as:

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Systolic on right

We can calculate the mean and deviation with the following formulas:

[te]\bar x = \frac{\sum_{i=1}^n X_i}{n}[/tex]

s= \frac{\sum_{i=1}^n (x_i -\bar X)^2}{n-1}

For this case we have the following values:

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So then the coeffcient of variation is given by:

\hat{CV} =\frac{12.65}{74.2}=0.170

So for this case we have more variation for the data of systolic on left compared to the data systolic on right but the difference is not big since 0.170-0.147 = 0.023.

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