Answer:
A. Acidic
B. Neutral
C. Basic
D. Acidic
E. Basic
Explanation:
The reaction of salts with water to give aqueous solutions which are either acidic, basic or neutral is known as salt hydrolysis. Salts that are produced from the reaction of strong acids and weak bases give acidic solutions. Salts that are produced the reaction between weak acids and strong bases give basic solutions. Neutral solutions are obtained from salts produced bynthe reaction of strong acids and strong bases.
The hydrolysis of the given salts are shown below:
A. AlCl₃ + 3 H₂O ---> 3 HCl + Al(OH)₃
The aqueous solution produced will be acidic since HCl is a strong acid while Al(OH)₃ is a weak base.
B. NaBr + H₂O ----> HBr + NaOH
The aqueous solution produced will be neutral since HBr is a strong acid and NaOH is strong base as well.
C. NaClO + H₂O ----> HClO + NaOH
The aqueous solution produced will be basic since HClO is a weak acid while NaOH is a strong base.
D. CH₃NH₃NO₃ + H₂O ----> HNO₃ + CH₃NH₂ + H₂O
The aqueous solution produced will be acidic since HNO₃ is a strong acid while CH₃NH₂ is a weak base.
E. Na₂SO₃ + 2 H₂O ----> H₂SO₃ + 2 NaOH
The aqueous solution produced will be basic since H₂SO₃ is a weak acid while NaOH is a strong base.
Boyle's law: in Boyle's law, pressure of a gas in inversely proportional to the volume while the temperature is shield constant
Gay-Lussac's law: In Gay-Lussac's law, pressure of a gas in directly proportional to the temperature while the volume is held constant.
Charles's law: In Charles's law, the volume of a gas is directly proportional to the temperature while the pressure is held constant.
Answer:Independent, dependent, and controlled variables.
Explanation:
The question incomplete , the complete question is:
A student dissolves of 18.0 g urea in 200.0 mL of a solvent with a density of 0.95 g/mL . The student notices that the volume of the solvent does not change when the urea dissolves in it. Calculate the molarity and molality of the student's solution. Round both of your answers to significant digits.
Answer:
The molarity and molality of the student's solution is 1.50 Molar and 1.58 molal.
Explanation:
Moles of urea = 
Volume of the solution = 200.0 mL = 0.2 L (1 mL = 0.001 L)

Molarity of the urea solution ;

Mass of solvent = m
Volume of solvent = V = 200.0 mL
Density of the urea = d = 0.95 g/mL


(1 g = 0.001 kg)
Molality of the urea solution ;


The molarity and molality of the student's solution is 1.50 Molar and 1.58 molal.
Answer:
Bacteria are also involved in many processes that are indispensable for our life on Earth. Many of these processes have to do with the recycling (reuse) of chemical elements that have been here since the formation of the planet
Explanation:
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