Answer:
Nonmetals lose electrons to gain a negative charge and form anions, whereas metals lose electrons to gain a postive charge and form cations.
Atoms that gain or lose electrons are called ions and can have a negative charge or a postive charge.
Explanation:
Answer:
636.86 K
Explanation:
From the question given above, the following data were obtained:
Initial temperature (T1) = 333 K
Initial pressure (P1) = 4 atm
Final pressure (P2) = 7.65 atm
Final temperature (T2) =?
NOTE: The volume is constant.
Since the volume is constant, we can obtain the new temperature the gas by using the following formula as illustrated below:
P1 /T1 = P2 /T2
4/333 = 7.65/T2
Cross multiply
4 × T2 = 333 × 7.65
4 × T2 = 2547.45
Divide both side by 4
T2 = 2547.45 / 4
T2 = 636.86 K
Therefore, the new temperature of the gas is 636.86 K
Answer:
84.30 mm Hg
Explanation:
In 100 cm³ of solution we have: 40 cm³ C6H6 and 60 cm³ CCl4. Given the densities we can calculate their masses and number of moles, and since by Raoult´s law
Ptotal = XAPºA + XBPºB
where XA= mol fraction =na/(na +nb) and PºA vapor pressure pure of pure component A
m C6H6 = 40 cm³ x 0.87865 g/cm³ = 35.146 g
mol C6H6 = 35.146 g/ 78.11 g/mol = 0.45 mol
mass CCl4 = 60 cm³ x 1.5940 g/cm³ = 95.640 g
mol CCl4 = 95.640 g / 153.82 g/mol = 0.62 mol
mol tot = 1.07
XC6H6 = 0.45/ 1.07 = 0.42 XCCl4 = 0.62/1.07 =0.58
Ptot (mmHg) = 0.42 x 74.61 + .58 x 91.32 = 84.30 mmHg
Answer:
18.8 g
Explanation:
The equation of the reaction is;
AgClO3(aq) + LiBr(aq)------>LiClO3(aq) + AgBr(s)
Number of moles of AgClO3 = 117.63 g/191.32 g/mol = 0.6 moles
Number of moles of LiBr = 10.23 g/86.845 g/mol = 0.1 moles
Since the molar ratio is 1:1, LiBr is the limiting reactant
Molar mass of solid AgBr = 187.77 g/mol
Mass of precipitate formed = 0.1 moles * 187.77 g/mol
Mass of precipitate formed = 18.8 g
Answer:
atoms are a part of the universe so they are like a ball, you can't put anything on top or it will fall
Explanation:
