Answer: 120.9 grams
Explanation:
Given the question : How many grams are in 3.67 moles of Lithium cyanide?
Chemical formula of lithium cyanide = LiCN
Molar mass of LiCN: Li = 6.941 ; C = 12, N = 14
LiCN = (6.941 + 12 + 14). = 32.941 g/mol
(Gram of substance / mole of substance) = (molar mass of substance / one mole)
(Gram of substance / 3.67) = (32.941 / 1)
= gram * 1 = 3.67 * 32.941
Gram of substance = 120.89347
= 120.9 grams
The small part of the nucleus where ribosomal subunit formation takes place is called the nucleolus. This structure is found in eukaryotic cells and takes up about 25 percent of the volume of the nucleus. This structure is said to be the brain of the nucleus. It is made up of ribobucleic acids or the RNA and proteins. Its primary function is to transcript the ribosomal RNA (rRNA) and to combine these with the proteins resulting to the formation of an incomplete ribosome. Since it is closely related to a chromosomal matter of a cell and important in the production of ribosome, this structure is correlated to be one of the cause of a number of diseases.
Answer:
9. Electron Affinity
10. The second option....
Answer : The correct option is B.
Explanation :
The temperature of the warm water is higher than the cold water. That means as the temperature of warm water increases, the kinetic energy of the warm water molecule also increases.
As the kinetic energy of the warm water molecule increases, the number of molecules conversion into a vapor also increases (i.e, quick evaporation), thereby increasing the vapor pressure of warm water.
Hence, the correct answer is, (B) Warm water evaporates more quickly.
Answer:
The concentration c is equal to Ka
Explanation:
The acid will ionize as observed in the following reaction:
HA = H+ + A-
H+ is the proton of the acid and A- is the conjugate base
. The equation to calculate the Ka is as follows:
Ka = ([H+]*[A -])/[HA]
Initially we have to:
[H+] = 0
[A-] = 0
[HA] = c
During the change we have:
[H+] = +x
[A-] = +x
[HA] = -x
During balance we have:
[H+] = 0 + x
[A-] = 0 + x
[HA] = c - x
Substituting the Ka equation we have:
Ka = ([H+]*[A-])/[HA]
Ka = (x * x)/(c-x)
x^2 + Kax - (c * Ka) = 0
We must find c, having as [H+] = 1/2c. Replacing we have:
(1/2c)^2 + (Ka * 1/2 * c) - (c * Ka) = 0
(c^2)/2 + Ka(c / 2 - c) = 0
(c^2)/2 + (-Ka * c/2) = 0
c^2 -(c*Ka) = 0
c-Ka = 0
Ka = c
