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1 year ago

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If the two triangles shown below are similar based on the giveninformation, complete the similarity statement, otherwise choose

the"Not Similar" button.А18 in9 inHB7 in14 inACAB-ANot Similar

1 answer:

SVETLANKA909090 [29]1 year ago

5 0

1) Two triangles are similar if they have congruent angles and proportional sides (for each corresponding leg).

2) So let's check whether there are similar triangles by setting a proportion:

$\begin{gathered} \frac{HC}{CA}=\frac{JH}{CB} \\ \frac{9}{18}=\frac{7}{14} \\ Simplify\text{ both:} \\ \frac{1}{2}=\frac{1}{2} \end{gathered}$

3) So yes they are similar, i.e. ΔCAB ~ΔHGJ

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Complete the table of inputs and outputs for the given function g(x) = 3 - 8x

NeX [460]

Answer:

See Explanation

Step-by-step explanation:

<em>The question is incomplete as the input and output values are not given. However, the question can still be solved by assuming both values</em>

Given

$g(x) = 3 - 8x$

In this case;

x represents the input while g(x) represents the output

Now, assume x = 2; Determine the output.

Here we simply substitute 2 for x in the above expression

i.e.

$g(x) = 3 - 8x$ becomes

$g(2) = 3 - 8(2)$

$g(2) = 3 - 16$

$g(2) = -13$

Similarly, if x = 5

$g(5) = 3 - 8(5)$

$g(5) = 3 - 40$

$g(5) = -37$

Also, let's assume g(x) = -21; Determine the input

$g(x) = 3 - 8x$ becomes

$-21 = 3 - 8x$

Solve for x

$-21 - 3 = -8x$

$-24 = -8x$

$x = \frac{-24}{-8}$

$x = 3$

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4 years ago

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grandymaker [24]

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4 years ago

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A liter is equal to centiliters. Is a centiliter a greater measure than milliliter?

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The answer would be yes. It takes 10 milliliters to make 1 centiliter.

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A cube has a length of 8 in. What is the width and the height of the cube?

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Answer:

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Step-by-step explanation:

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Explain how to estimate the quotient using compatible<br>numbers.plz help fast

Nadya [2.5K]

<h2><u>PLEASE MARK BRAINLIEST!</u></h2>

Answer:

To estimate the quotient, make the fractions "like" fractions. To do this, you need to make the fractions have the same denominator, and turn them into improper fractions.

Step-by-step explanation:

$27\frac{2}{3} = 27 \frac{20}{30}$

$3\frac{9}{10} = 3\frac{27}{30}$

Now the denominators are the same --> they are "like" fractions.

$27\frac{20}{30} + 3\frac{27}{30} = ?$

$27\frac{20}{30} + 3\frac{27}{30} = (27 + 3) + (\frac{20}{30} + \frac{27}{30})$

$27\frac{20}{30} + 3\frac{27}{30} = (30) + (\frac{47}{30})$

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