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ohaa [14]
2 years ago
10

Please help me!!!!!!!!!!!

Mathematics
1 answer:
Zarrin [17]2 years ago
8 0
Hi! The answer should be (5,0) (1,0) hope that helps!
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3/19​% of a quantity is equal to <br> blank of the quantity.
geniusboy [140]

Answer:

.15 percent

Step-by-step explanation:

I just divided 3 by 19 and set them equivalent to each other.

4 0
3 years ago
❤️❤️help please ASAP
Archy [21]
From what i see, i guess the answer may be B. it looks like it, but i dont really know.
6 0
3 years ago
Read 2 more answers
Polly's Polls asked 1850 second-year college students if they still had their original major. According to the colleges, 65% of
suter [353]

Answer:

The probability that Polly's Sample will give a result within 1% of the value 65% is 0.6424

Step-by-step explanation:

The variable that assigns the value 1 if a person had its original major and 0 otherwise is a Bernoulli variable with paramenter 0.65. Since she asked the question to 1850 people, then the number of students that will have their original major is a Binomial random variable with parameters n = 1850, p = 0.65.

Since the sample is large enough, we can use the Central Limit Theorem to approximate that random variable to a Normal random variable, which we will denote X.

The parameters of X are determined with the mean and standard deviation of the Binomal that we are approximating. The mean is np = 1850*0.65 = 1202.5, and the standard deviation is √np(1-p) = √(1202.5*0.35) = 20.5152.

We want to know the probability that X is between 0.64*1850 = 1184 and 0.66*1850 = 1221 (that is, the percentage is between 64 and 66). In order to calculate this, we standarize X so that we can work with a standard normal random variable W ≈ N(0,1). The standarization is obtained by substracting the mean from X and dividing the result by the standard deviation, in other words

W = \frac{X-\lambda}{\sigma} = \frac{X-1202.5}{20.5152}

The values of the cummulative function of the standard normal variable W, which we will denote \phi are tabulated and they can be found in the attached file.

Now, we are ready to compute the probability that X is between 1184 and 1221. Remember that, since the standard random variable is symmetric through 0, then \phi(-z) = 1-\phi(z) for each positive value z.

P(1184 < X < 1221) = P(\frac{1184-1202.5}{20.5152} < \frac{X-1202.5}{20.5152} < \frac{1221-1202.5}{20.5152})\\ = P(-0.9018 < W < 0.9018) = \phi(0.9018) - \phi(-0.9018) = \phi(0.9018)-(1-\phi(0.9018))\\ = 2\phi(0.9018)-1 = 2*0.8212-1 = 0.6424

Therefore, the probability that Polly's Sample will give a result within 1% of the value 65% is 0.6424.

Download pdf
4 0
3 years ago
Jacob is asked to solve the follow problem: "Kayla is 9 years older than twice Hannah’s age. If the difference in their ages is
tatiyna

Answer:

Step-by-step explanation:

k = 2h+9

h+16=k

h+16=2h+9

-h = -7

h = 7

hannah is 7 and kayla is 23

jacob is wrong because if u do 16*2+7 it’s 39 and 39-16 does not equal 16

6 0
3 years ago
Record for Boston Marathon's wheelchair division is 1 hour, 18 minutes, and 27 seconds.
aleksley [76]
1 hr 18 minutes and 27 seconds hmmm

there are 60 minutes in 1 hr, thus 18 minutes is 18/60 hrs or 0.3hr.

so 1hr 18min is 1.3 hrs

there are 60 seconds in 1 minute and 60 minutes in 1 hr, thus 60*60 seconds in 1hr, or 3600 seconds, so, 27 seconds is just 27/3600 hrs, or 0.0075 hrs.

so, 1.3 hr or 1.3000 hr for that matter plus 0.0075, is just 1.3075 hrs.

a)

so, they covered 26.2 miles in 1.3075 hrs, so the average speed is just 26.2/1.3075, or about 20.0382409177 miles/hr

b)

\bf \begin{array}{ccll}&#10;miles&hrs\\&#10;\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\&#10;26.2&1.3075\\&#10;30&h&#10;\end{array}\implies \cfrac{26.2}{30}=\cfrac{1.3075}{h}\implies h=\cfrac{1.3075\cdot 30}{26.2}

8 0
3 years ago
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