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nata0808 [166]
1 year ago
7

The city of Townsville has a population of 2 million in 2002, which is growing at 6% per year.A) Write a recursive formula for t

he population of Townsville.B) Write an explicit formula for the population of Townsville.C) how many people will there be in 2011, rounding to the nearest tenth of a million?
Mathematics
1 answer:
inna [77]1 year ago
4 0

Given:

Population in 2002 is 2 million and is growing at 6%per year.

A)

Recursive formula:

P_n=P_{n-1}(1+\frac{6}{100})P_n=P_{n-1}(\frac{100+6}{100})P_n=P_{n-1}(\frac{53}{50})P_0=2.2\text{ }P_n=P_{n-1}(1.06)

B)

P_1=P_0(1.06)P_2=P_1(1.06)P_2=P_0(1.06)_{}(1.06)P_2=2.2(1.06)^2_{}P_n=2.2(1.06)^n_{}

C)

n=2011-2002

n=9

No\text{ of people in 2011=}2.2(1.06)^9No\text{ of people in 2011=}3.7\text{ millon}

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ii). k = 10 with the probability of $\frac{1}{4}$

iii). k = 10 with the probability $\frac{1}{2}$

So the probability of at least two person out of the 'n' born people in same month is  = 1 - P (none of the n born in the same month)

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= 0.903547

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=P(k=10 and at least 2 born in the same month)/P(at least 2 share their birthday in same month)

= $0.25 \times \frac{0.996132}{0.903547}$

= 0.0.275617

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