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3 years ago

Can someone help me plz

Mathematics

1 answer:

bija089 [108]3 years ago

4 0

Answer:

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At a summer camp the ratio of cabins to campers is 15 to 255 and equal number of campers are staying in each cabin how many camp

GarryVolchara [31]

There are 17 campers per cabin. I found it by dividing 15 and 255 by 15 to find how many people per one cabin.

4 0

3 years ago

Read 2 more answers

The position equation is s = -16t^2 + vot + so where s is height of the object in feet, vo is the initial velocity of the object

Hunter-Best [27]

A. For this case, let us set the variables:

s = 0 (final destination on the ground)

t = unknown

vo = 0

so = 8000 ft

Using the equation, we calculate for t:

0 = -16 t^2 + 0t + 8000

t = 22.36 s

B. For this case:

s = unknown

t = 22.36 s

vo = 600 miles/hr = 880 ft/s

so = 0

Using the equation, we calculate for s:

s = -16*(22.36)^2 + 880*22.36 + 0

s = 11, 677.29 ft = 2.21 miles

6 0

3 years ago

Can anyone help with what the formula to calculate the volume of a Rhombohedron (3D Rhombus) is? Could you also give me an examp

Elza [17]

Answer: the formula is : β = 180° - α

A = 6 * a² * sin(α)

V = a³ * (1-cos(α)) * √1+2cos(α)

Sorry, i don't know any examples .

Step-by-step explanation:

4 0

2 years ago

One model for the spread of a virusis that the rate of spread is proportional to the product of the fraction of the population P

Darya [45]

Answer:

The differential equation for the model is

$\frac{dP}{dt}=kP(1-P)$

The model for P is

$P(t)=\frac{1}{1-0.99e^{t/447}}$

At half day of the 4th day (t=4.488), the population infected reaches 90,000.

Step-by-step explanation:

We can write the rate of spread of the virus as:

$\frac{dP}{dt}=kP(1-P)$

We know that P(0)=100 and P(3)=100+200=300.

We have to calculate t so that P(t)=0.9*100,000=90,000.

Solving the diferential equation

$\frac{dP}{dt}=kP(1-P)\\\\ \int \frac{dP}{P-P^2} =k\int dt\\\\-ln(1-\frac{1}{P})+C_1=kt\\\\1-\frac{1}{P}=Ce^{-kt}\\\\\frac{1}{P}=1-Ce^{-kt}\\\\P=\frac{1}{1-Ce^{-kt}}$

$P(0)= \frac{1}{1-Ce^{-kt}}=\frac{1}{1-C}=100\\\\1-C=0.01\\\\C=0.99\\\\\\P(3)= \frac{1}{1-0.99e^{-3k}}=300\\\\1-0.99e^{-3k}=\frac{1}{300}=0.99e^{-3k}=1-1/300=0.997\\\\e^{-3k}=0.997/0.99=1.007\\\\-3k=ln(1.007)=0.007\\\\k=-0.007/3=-0.00224=-1/447$

Then the model for the population infected at time t is:

$P(t)=\frac{1}{1-0.99e^{t/447}}$

Now, we can calculate t for P(t)=90,000

$P(t)=\frac{1}{1-0.99e^{t/447}}=90,000\\\\1-0.99e^{t/447}=1/90,000 \\\\0.99e^{t/447}=1-1/90,000=0.999988889\\\\e^{t/447}=1.010089787\\\\ t/447=ln(1.010089787)\\\\t=447ln(1.010089787)=447*0.010039225=4.487533$

At half day of the 4th day (t=4.488), the population infected reaches 90,000.

8 0

3 years ago

Instructions: Find tire slope between the two points given. Then, use the slope and one of the points to write the equation of t

faust18 [17]

Answer:

Equation: y = 2x — 3

Slope: 2

Y-intercept: —3

Step-by-step explanation:

m=∆y/∆x

= —3—(—1)/0—1

= —2/—1

= 2

We Know: y - y0 = m (x—x0)

y — (—3) = 2 (x — 0)

y + 3 = 2x

y = 2x — 3

Equation: y = 2x — 3

Slope: 2

Y-intercept: —3

8 0

2 years ago

Can someone help me plz ​

Can someone help me plz