Let x and x+1 represent the consecutive integers, then x is the other leg and x+1 is the hypotenuse (because the hypotenuse must be greater than its sides).
Use Pythagorean Theorem:
a² + b² = c²
(77)² + x² = (x+1)²
5929 + x² = x² + 2x + 1
5928 = 2x
2964 = x
x+1 = 2965
Answer: The other leg is 2964 m and the hypotenuse is 2965 m
<span>Minimal residual cancer cells may not be detected in surgical margins of oral squamous cell carcinoma (OSCC) with routine histological examination. Using molecular markers at surgical margins can be helpful. We attempted to evaluate the MMP-9 and E-cadherin expression in OSCC samples and tumor-free surgical margins and association with clinicopathological factors. We examined E-cadherin and MMP-9 expression in 58 OSCCs including 19 grade I, 21 grade II and 18 grade III with histological tumor-free surgical margins by immunohistochemistry. Specimens were also divided in two groups: 19 samples as an early and 39 as an advanced stage. For E-cadherin in OSCCs and surgical margins, significant difference was observed between poor and moderate tumor differentiation. Different stages of OSCC demonstrated significant differences with higher expression in early stage tumors. For surgical margins, 82.1% of advanced and 84.2% of early stage samples demonstrated immunoreactivity. Both OSCC samples and surgical margins demonstrated significant differences for MMP-9 between stages with higher immunoreactivity in advanced stage, whereas there were not differences between different grades in surgical margins. E-cadherin and MMP-9 expression at histologically negative surgical margins shows the significance of these markers for prognostic values in OSCC patients with E-cadherin being the preferred predictor.</span>
Answer:
y-intercept: [0, -2]; 0 = m
Step-by-step explanation:
Anything set to equal <em>y</em><em> </em>is what is known as a zero <em>rate</em><em> </em><em>of</em><em> </em><em>change</em><em> </em>[<em>slope</em>] because it is a horizontal line.
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The answer is x = 30 mm.
Similar shapes have proportional measurements. Hence:
side AB/side BC = side DE/side EF
1.) Substitute with given:
<span> AB/BC = DE/EF
10/4 = DE/12
2.) Cross multiply </span>10/4 = DE/12<span>
4DE = 120
3.) Divide both sides of the equation by 4 </span>to solve for DE:<span>
4DE/4 = 120/4
DE = 30 mm.
4.) Substitute and cross multiply to check if the values are equal:
</span> AB/BC = DE/EF
10/4 = 30/12
4(30) =10(12)
120 = 120
Answer:
Your answer is
tangent ratio of B is 3/2
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Step-by-step explanation: