Answer:
Step-by-step explanation:
Corresponding parts of the congruent triangles are congruent [CPCTC]
By using this property of congruent triangles,
15). ΔABC ≅ ΔABR
BC ≅ BR [By CPCTC]
16). ΔJIH ≅ ΔJIW
∠HJI ≅ ∠WJI [By CPCTC]
17). ΔBDC ≅ ΔBDJ
∠CBD ≅ ∠JBD [By CPCTC]
Answer:
The volume of a right circular cylinder with a base diameter of 17.5 ft and a height of 24.5 ft is:
5889.95 ft³
Step-by-step explanation:
We are given a base diameter of a right circular cylinder as :
d = 17.5 ft.
hence radius of cylinder i.e. r =d/2 = 8.75 ft.
height of the cylinder = 24.5 ft.
now we know that volume of cylinder i.e. V is given by :
V = πr²h
putting the value of r and h in the given formula to obtain the volume
V = 3.14×(8.75)²×24.5
= 5889.95 ft³
hence, the volume of a right circular cylinder with a base diameter of 17.5 ft and a height of 24.5 ft is:
5889.95 ft³
6a+ 12b+ 18c
Hope this is correct...plz let me know
Answer:
P(A) = 86/100
P(B) = 79/100
P(A') = 14/100
P(A U B) = 95/100
P(A' U B) = 84/100
Step-by-step explanation:
i. P(A) = number of disks with high shock resistance/total number of disks
= (70+16)/100
= 86/100
ii. P(B) = number of disks with high scratch resistance/total number of disks
= (70+9)/100
= 79/100
iii. P(A') = number of disks without high shock resistance/total number of disks
= (100-86)/100
= 14/100
iv. P(AUB) = number of disks with high shock resistance or high scratch resistance/total number of disks
= (70+9+16)/100
= 95/100
v. P(A'UB) = number of disks without high shock resistance or with high scratch resistance/total number of disks
= (5+9+70)/100
= 84/100
