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EastWind [94]
3 years ago
10

you are given a fraction in simplest form. the numerator is not zero.when you write the fraction as a decimal,it is a repeating

decimal. which numbers from 1 to 10 could be the denominator
Mathematics
1 answer:
PolarNik [594]3 years ago
3 0

Answer:

3, 6, 7, 9

Step-by-step explanation:

We can take a look at each value from 1 to 10

We see that for 3, 6, 7, and 9 the decimal repeats forever for some numerators. For example, 1/3 repeats forever, 4/6 repeats forever, 5/7 repeats forever, 1/9 repeats forever.

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a molecule is measured and the width is 3x10-6 cm. how long will a string of 225 similar molecule be? give your answer in scient
mixer [17]

The length of the molecule is 6.75*10^-^4cm in scientific notation.

Data;

  • Width of molecule = 3*10^-6 cm
  • Number of molecules = 225

<h3>Length of the molecule</h3>

This can be calculated as the total length of the 225 molecules added together. To do this, we simply multiply both the numbers of the molecules by the width of the molecule.

This becomes;

3*10^-^6*225 = 0.000675cm = 6.75*10^-^4cm

The length of the molecule is 6.75*10^-^4cm in scientific notation.

Learn more on scientific notation here;

brainly.com/question/5756316

brainly.com/question/1712028

7 0
2 years ago
Is a relation always a function? Is a function always a relation? Explain.
katen-ka-za [31]

A function is always a relation but relation is not always a function

<u>Solution:</u>

Given that, we have to explain Is a relation always a function and is a function always a relation

Note that both functions and relations are defined as sets of lists.  

In fact, every function is a relation. However, not every relation is a function.  A relation from a set X to a set Y is called a function if each element of X is related to exactly one element in Y.

That is, given an element x in X, there is only one element in Y that x is related to.

For example, consider the following sets X and Y. Let me give you a relation between them that is not a function;

X = { 1, 2, 3 }

Y = { a , b , c, d }

Relation from X to Y : { (1,a) , (2, b) , (2, c) , (3, d) }

This relation is not a function from X to Y because the element 2 in X is related to two different elements, b and c

Relation from X to Y that is a function: { (1,d) , (2,d) , (3, a) }

This is a function since each element from X is related to only one element in Y. Note that it is okay for two different elements in X to be related to the same element in Y. It's still a function, it's just not a one-to-one function.

So, we can say that function is a type of relation.

Which means whatever a function occurs, it will be a relation from one set to other.

But when a relation occurs it may be a function but need not be always a function.

Hence, a function is always a relation but relation is not always a function.

8 0
3 years ago
Find the Quotient and Remainder. 5x^3 - 6x^2 + x + 7 divided by x^2
12345 [234]

Step-by-step explanation:

Solution

According to remainder theorem, when f(x) is divided by (x+2), Remainder =f(−2)

f(x)=5x3+2x2−6x+12

f(−2)=5(−2)3+2(−2)2−6(−2)+12

=5×−8+2×4+12+12

=−40+32=−8

∴ Remainder=−8

5 0
2 years ago
What's the answer and show your work by using the funnel method
Paraphin [41]
Answer: i got 44 for the answer
5 0
2 years ago
Retro Rides is a club for owners of vintage cars and motorcycles. Every year the club gets together for a ride. This year, 53 ve
kari74 [83]
21 cars, 32 motorcycles.
create a system of equations using x for cars and y for motorcycles.
\left \{ {{x+y=53} \atop {4x+2y=148}} \right.
multiply the top equation by 2 to prepare for elimination method
\left \{ {{2x+2y=106} \atop {4x+2y=148}} \right.
subtract terms
\left \{ {{2x+2y=106} \atop {-4x-2y=-148}} \right.  = (-2x = -42)
divide both sides by negative 2 to solve for x
x =21
plug in x  into original equation to solve for y.
21 + y = 53
subtract both sides by 21
y=32



8 0
3 years ago
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