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Phantasy [73]
1 year ago
7

1. Plot two points to form a square in the above graph. Label the points R and S. A square is a quadrilateral with all four side

s of the same length. After plotting the points, trace the square by connecting the points.

Mathematics
1 answer:
Mariana [72]1 year ago
5 0

ANSWER and EXPLANATION

We want to plot two points to form a square.

So, we will have square PQRS with sides PQ, QR, RS and SP.

Because it is a square, we have that all the lines must be the same length.

Because each of the lines are perpendicular to one another, we will have that the slope of one will be the negative inverse of the preceeding line.

We will find one point R such that the line between that point and Q is perpendicular to PQ and another point S such that the line between that point and P is perpendicular to RS.

Negative inverse slope here is going to be applied in such a way that we invert the change in y and change in x between each line while alternating the negative sign.

From observing the line PQ, we see that the change of x and y from P to Q is:

(x + 2, y - 7)

i.e P(-4, 4) => Q(-4 + 2, 4 - 7) = Q(-2, -3)

Therefore, for the next point R, since the slope of QR is the negative inverse of PQ, it will become that the change from x and y from Q to R is:

(x + 7, y + 2)

i.e Q(-2, -3) => R(-2 + 7, -3 + 2) = R(5, -1)

The same principle applies for S, we use the negative inverse:

(x - 2, y + 7)

i.e R(5, -1) => S(5 - 2, -1 + 7) = S(3, 6)

Therefore, the two points are R(5, -1) and S(3, 6)

The graph is given below:

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Step-by-step explanation:

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A baseball is hit and its height is given by h = 29.4t – 4. 9t^2, where h is the
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Answer:

44.1m

Step-by-step explanation:

we are given a quadratic function which represents the height and time of a baseball

\displaystyle h = 29.4t - 4.9 {t}^{2}

we want to figure out maximum height of

the baseball

since the given function is a quadratic function so we have a parabola

which means figuring out the maximum height is the same thing as figuring out the maximum y coordinate (vertex)

to do so we can use some special formulas

recall that,

\displaystyle \rm t= \frac{ - b}{  2a}

\displaystyle H_{\text{max}}=f(t)

notice that, our given function is not in standard form i.e

\displaystyle f(x) = a {x}^{2}  + bx + c

let's make it so

\displaystyle h =  - 4.9 {t}^{2}  + 29.4t

therefore we got

our <em>a</em> is -4.9 and <em>b </em>is 29.4

so substitute:

\displaystyle\rm t=  \frac{ -( 29.4)}{  2 \cdot - 4.9}

remove parentheses and change its sign:

\displaystyle\rm t=  \frac{ -29.4}{  2 \cdot - 4.9}

simplify multiplication:

\displaystyle\rm t=  \frac{ -29.4}{  - 9.8}

simplify division:

\displaystyle  \: t  = 3

so we have figured out the time when the baseball will reach the maximum height

now we have to figure out the height

to do so

substitute the got value of time to our given function

\displaystyle H_{\text{max}}=29.4\cdot 3-4.9\cdot {3}^2

simplify square:

\displaystyle H_{\text{max}}=29.4\cdot 3-4.9\cdot 9

simplify mutilation:

\displaystyle H_{\text{max}}=88.2-44.1

simplify substraction:

\displaystyle H_{\text{max}}=44.1

hence,

the maximum height of the baseball is 44.1 metres

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Answer:

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