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3 years ago

I need to know the answer to a,b,c,and d

Mathematics

1 answer:

GalinKa [24]3 years ago

6 0

14,28,42,56 part A. part b idk

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For a beverage, Lisa mixes cups of lemonade to cups of iced tea in a ratio of 1:4. Which of the following best describes the amo

dybincka [34]

There is one cup of lemonade to four cups of iced tea.

3 0

3 years ago

A pack of 6 batteries of the same type cost ?2.79 . By calculating the price per battery,determine if this is better value.You m

MissTica

Answer:

The full question is attached in the picture below.

The better price for the battery is given with the 6 pack.

(£ 0.47 per battery)

Step-by-step explanation:

If 8 batteries cost £ 3.99

This means that one battery is equal to

£3.99/8 = £ 0.49875 ≈ £ 0.50 per battery

The pack of 6 batteries costs £ 2.79

This means that one battery is equal to

£2.79/6 = £ 0.465 ≈ £ 0.47 per battery

Then, we can conclude than the 6 pack gives us a better price per battery

7 0

3 years ago

Suppose integral [4th root(1/cos^2x - 1)]/sin(2x) dx = A<br>What is the value of the A^2?<br><br>

Alla [95]

$\large \mathbb{PROBLEM:}$

$\begin{array}{l} \textsf{Suppose }\displaystyle \sf \int \dfrac{\sqrt[4]{\frac{1}{\cos^2 x} - 1}}{\sin 2x}\ dx = A \\ \\ \textsf{What is the value of }\sf A^2? \end{array}$

$\large \mathbb{SOLUTION:}$

$\!\!\small \begin{array}{l} \displaystyle \sf A = \int \dfrac{\sqrt[4]{\frac{1}{\cos^2 x} - 1}}{\sin 2x}\ dx \\ \\ \textsf{Simplifying} \\ \\ \displaystyle \sf A = \int \dfrac{\sqrt[4]{\sec^2 x - 1}}{\sin 2x}\ dx \\ \\ \displaystyle \sf A = \int \dfrac{\sqrt[4]{\tan^2 x}}{\sin 2x}\ dx \\ \\ \displaystyle \sf A = \int \dfrac{\sqrt{\tan x}}{\sin 2x}\ dx \\ \\ \displaystyle \sf A = \int \dfrac{\sqrt{\tan x}}{\sin 2x}\cdot \dfrac{\sqrt{\tan x}}{\sqrt{\tan x}}\ dx \\ \\ \displaystyle \sf A = \int \dfrac{\tan x}{\sin 2x\ \sqrt{\tan x}}\ dx \\ \\ \displaystyle \sf A = \int \dfrac{\dfrac{\sin x}{\cos x}}{2\sin x \cos x \sqrt{\tan x}}\ dx\:\:\because {\scriptsize \begin{cases}\:\sf \tan x = \frac{\sin x}{\cos x} \\ \: \sf \sin 2x = 2\sin x \cos x \end{cases}} \\ \\ \displaystyle \sf A = \int \dfrac{\dfrac{1}{\cos^2 x}}{2\sqrt{\tan x}}\ dx \\ \\ \displaystyle \sf A = \int \dfrac{\sec^2 x}{2\sqrt{\tan x}}\ dx, \quad\begin{aligned}\sf let\ u &=\sf \tan x \\ \sf du &=\sf \sec^2 x\ dx \end{aligned} \\ \\ \textsf{The integral becomes} \\ \\ \displaystyle \sf A = \dfrac{1}{2}\int \dfrac{du}{\sqrt{u}} \\ \\ \sf A= \dfrac{1}{2}\cdot \dfrac{u^{-\frac{1}{2} + 1}}{-\frac{1}{2} + 1} + C = \sqrt{u} + C \\ \\ \sf A = \sqrt{\tan x} + C\ or\ \sqrt{|\tan x|} + C\textsf{ for restricted} \\ \qquad\qquad\qquad\qquad\qquad\qquad\quad \textsf{values of x} \\ \\ \therefore \boxed{\sf A^2 = (\sqrt{|\tan x|} + c)^2} \end{array}$

$\boxed{ \tt \red{C}arry \: \red{ O}n \: \red{L}earning} \: \underline{\tt{5/13/22}}$

4 0

2 years ago

Find the sum of these polynomials.

Genrish500 [490]

Answer:

Step-by-step explanation:

add the two x^2 parts = 10 x^2

so answer is B or C

add the constants 7 + 6 = 13 so answer C

7 0

2 years ago

Read 2 more answers

Aleah's rectangular garden borders a wall. She buys 80 m of fencing. What are the dimensions of the garden that will maximize it

Arada [10]

Hello!

The dimensions that maximize its area is when the width and the length are the same

The dimensions for the highest area is 40 x 40

The answer is 40 by 40

Hope this helps!

7 0

3 years ago