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Allushta [10]
1 year ago
9

a constant current of 3 a for 4 hours is required to charge an automotive battery.if the terminal voltage is 10 t/2 v, where t i

s in hours, how much charge is transported as a result of the charging?
Physics
1 answer:
Korvikt [17]1 year ago
3 0

The charge transported as a result of charging is 43200C .

we can note the following data from the statement :

Current (i) = 3A

Time interval (t) = 4 hrs = 14400secs

As we know ,

Current is defined as the rate of flow of the charges between two points when a potential difference is applied between them.

Mathematically , it can be written as

Current(i) = charge (q)/ time(t)

Q = i × t

   = 3 × 14400

   = 43200 C

By dividing the value of the current passed through the circuit by the time for which the charge is passed gives out the value of the charge passed .

learn more on charges :

brainly.com/question/15238352

#SPJ4

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Write any two uses of plane mirrors?​
dexar [7]

Answer:

<h2>Uses of plane mirrors</h2>

They are used in periscopes, for signalling, in kaleidoscopes, to see round dangerous bends, in meters, as mirror tiles, in a sextant, in an overhead projector, an SLR camera, car wing mirrors, in microscopes and as reflecting number plates to mention only some!

Explanation:

Hope it is helpful....

6 0
3 years ago
Read 2 more answers
Three identical balls are thrown from the same height off a tall building. They are all thrown with the same speed, but in diffe
koban [17]

Answer:

three balls have the same speed

Explanation:

In a parabolic motion we have that

v_{x}=v_{0}cos\alpha\\v_{y}=-gt+v_{0}sin\alpha\\v=\sqrt{v_{x}^{2}+v_{y}^{2}}\\

but the time just before the balls hit the ground is

t=\frac{2v_{0}sin\alpha}{g}

Hence we have

ball A

v=\sqrt{v_{0}^{2}cos^{2}(0)+(-g\frac{2v_{0}sin(0)}{g}+v_{0}sin(0))^{2}}\\v=\sqrt{v_{0}^{2}}=v_{0}

ball B

v=\sqrt{v_{0}^{2}cos^{2}(45)+(-g\frac{2v_{0}sin(45)}{g}+v_{0}sin(45))^{2}}\\v=\sqrt{v_{0}^{2}(\frac{\sqrt{2}}{2})^{2}+v_{0}^{2}(\frac{\sqrt{2}}{2})^{2}}\\v=\sqrt{v_{0}^{2}}=v_{0}

ball C

v=\sqrt{v_{0}^{2}cos^{2}(-45)+(-g\frac{2v_{0}sin(-45)}{g}+v_{0}sin(-45))^{2}}\\v=\sqrt{v_{0}^{2}(\frac{\sqrt{2}}{2})^{2}+v_{0}^{2}(\frac{\sqrt{2}}{2})^{2}}\\v=\sqrt{v_{0}^{2}}=v_{0}

Hence, all three balls have the same speed just before hit the groug

vA=vB=vC

I hope this is useful for you

regards

5 0
3 years ago
Consider a 24.0 V storage battery that can transfer, over the course of its useful lifetime, a total charge equivalent to 340000
xeze [42]

Answer:

Explanation:

Given that,

Potential difference of battery is

V = 24V

Total charge battery can transferred

q = 340,000C

Work done by the battery?

Work done is given as

W = qV

Where q is charge in Columbs

V is potential difference in Volts

Then, W = qV

W = 340,000×24

W = 8,160,000 J

Work done by the battery over it's useful life time is 8,160,000J

5 0
3 years ago
In a game of ice hockey, you use a hockey stick to hit a puck of mass 0.16 kg that slides on essentially frictionless ice. Durin
Grace [21]

Answer:

12N

Explanation:

given- mass, acelation

Fnet=ma= .16kg*75m/s2

Fnet=12 N only force no friction given.

8 0
3 years ago
For a wavelength of 420 nm, a diffraction grating produces a bright fringe at an angle of 24°. For an unknown wavelength, the sa
Inessa [10]

Answer:

649.8420 nm

Explanation:

We have given \Theta _1=24^{\circ} \ and\ \Theta _2=39^{\circ}

\lambda _1=420\ nm we have to find unknown wavelength that is \lambda _2

The condition for constructive interference is dsin\Theta =n\lambda

Where d is distance between slits \Theta is angle of emergence and n is order of maxima

Using constructive interference equation

dsin\Theta _1=n\lambda _1 ---------eqn 1

dsin\Theta _2=n\lambda _2---------eqn 2

On dividing eqn 1 by eqn 2

\frac{\lambda _1}{\lambda _2}=\frac{sin\Theta _1}{sin\Theta _2}

\frac{420}{\lambda _2}=\frac{sin24^{\circ}}{sin39^{\circ}}

\lambda _2=649.8420\ nm  

7 0
3 years ago
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