For calculating work, the force and the distance must be in the same direction
Explanation:
The work done by a force on an object is given by the equation
where
F is the magnitude of the force
d is the displacement
is the angle between the direction of the force and of the displacement
The equation can be rewritten as
where is the component of the force parallel to the displacement of the object. This means that when calculating the work, only the component of the force parallel to the motion of the object contributes to the work: in this sense, we can say then for work to be different from zero, the force must have a component in the same direction as the motion of the object.
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The magnitude of normal force that floor exerts on chair is 100.83N
<u>Explanation:</u>
Given:
Weight of chair, W = 75N
Applied force, F = 42N
Angle, θ = 38°
Normal force, n = ?
We know,
Vertical component of the force = F sinθ
= 42 X sin38°
= 42 X 0.615
= 25.83N
Total normal force acting on the chair = 75N + 25.83N
= 100.83N
Therefore, the magnitude of normal force that floor exerts on chair is 100.83N
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Explanation:
A projectile is an object upon which the only force is gravity. The horizontal motion of the projectile is the result of the tendency of any object in motion to remain in motion at constant velocity. Due to the absence of horizontal forces, a projectile remains in motion with a constant horizontal velocity.
Answer:
(a) E = [2ξ] / [1+2]]
(b) S = k.ln(1+2) + [ξ] / T[1+2]]
(c) S = k.ln 3 (These values directly obtained from the result of (b) when T⇒0 & T⇒∞.)
Explanation:
Given:
One of three quantum states labeled by the quantum numbers m,
Where m = -1 , 0 or 1
A nucleus has the same energy E= e in the state m = 1 & m = -1
Compared with an energy E = 0 in the state m = 0.