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MissTica
4 years ago
14

Over a span of 6.0 seconds, a car changes its speed from 89 km/h to 37 km/h. What is its average acceleration in meters per seco

nd squared (m/s2)?
Physics
1 answer:
faltersainse [42]4 years ago
6 0

Answer: Average acceleration is -2.407 \frac{m}{s^{2}}

 

Explanation:

Average acceleration is equal to change in velocity divided by time taken

therefore, a=\frac{Vf-Vi}{t}

=> a=\frac{37-89}{6}\times \frac{5}{18}\frac{m}{s^{2}} = -2.407 \frac{m}{s^{2}}

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The maximum pressure variations the human ear can withstand are about how much above and below atmospheric pressure?
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The maximum pressure variations the human ear can withstand  above and below atmospheric pressure is around 30 pa. the normal atmospheric pressure is around 101325 pa. hence the variation in the maximum pressure for human ear is very small as compared to the atmospheric pressure. if the ear is exposed to a pressure greater than this , it can cause permanent damage to the ear.

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3 years ago
A woman holds a book by placing it between her hands such that she presses at right angles to the front and back covers. The boo
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Answer:

Explanation:

In order to solve this problem we need to make a free body diagram of the book and the forces that interact on it. In the picture below you can see the free body diagram with these forces.

The person holding the book is compressing it with his hands, thus exerting a couple of forces of equal magnitude and opposite direction with value F.

Now the key to solving this problem is to analyze the equilibrium condition (Newton's third law) on the x & y axes.

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3 years ago
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3 years ago
Starting from rest, a car undergoes a constant acceleration of 6 m/s^2. How far will the car travel in the two seconds?
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2 years ago
A transformer is intended to decrease the value of the alternating current from 500 amperes to 25 amperes. The primary coil cont
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Answer:

The number of turns in secondary coil is 4000

Explanation:

Given:

Current in primary coil I_{P} = 500 A

Current in secondary coil I_{S} = 25 A

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In case of transformer the relation between current and number of turns is given by,

     \frac{N_{S} }{N_{P}  } = \frac{I_{P} }{I_{S} }

For finding number of turns in secondary coil,

     N_{S} = \frac{I_{P} }{I_{S} }  N_{P}

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Therefore, the number of turns in secondary coil is 4000

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3 years ago
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