Question

Over a span of 6.0 seconds, a car changes its speed from 89 km/h to 37 km/h. What is its average acceleration in meters per second squared (m/s2)?

Answer 1

Answer: Average acceleration is -2.407 $\frac{m}{s^{2}}$

 

Explanation:

Average acceleration is equal to change in velocity divided by time taken

therefore, $a=\frac{Vf-Vi}{t}$

=> $a=\frac{37-89}{6}\times \frac{5}{18}\frac{m}{s^{2}} = -2.407 \frac{m}{s^{2}}$