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prisoha [69]
3 years ago
14

In a litter of 8 puppies, suppose there are 2 brown females, 2 brown males, 1 spotted female, and 3 spotted males. If a puppy is

randomly selected, what is the probability of selecting a female or a brown puppy?
Mathematics
2 answers:
Alexandra [31]3 years ago
7 0
There is a total of eight puppies. there are two female and brown puppies, one additional female puppy, and two additional brown puppies. so the number of possible wanted outcomes is 5. the probability is 5/8 or 62.5 %
tigry1 [53]3 years ago
3 0

Answer:

spotted male

Step-by-step explanation:

if you look at the numbers then you will see that this one has the biggest number

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Marlin Davies buys a truck for $28,000. In three years, the truck depreciates 48% in value. How much is the truck worth in three
harkovskaia [24]

In three years the Marlin's truck is worth 13,440$

To find percentage of a number, multiple it with in 0. Of the number.

Example: 28,000 ×. 48

That equals 13,440

So 48% of 28,000 is 13,440

5 0
3 years ago
Read 2 more answers
Sketch the general shape of each function. Then state the end behavior of the function.
nikdorinn [45]
Both the general shape of a polynomial and its end behavior are heavily influenced by the term with the largest exponent. The most complex behavior will be near the origin, as all terms impact this behavior, but as the graph extends farther into positive and/or negative infinity, the behavior is almost totally defined by the first term. When sketching the general shape of a function, the most accurate method (if you cannot use a calculator) is to solve for some representative points (find y at x= 0, 1, 2, 5, 10, 20). If you connect the points with a smooth curve, you can make projections about where the graph is headed at either end.
 End behavior is given by:
1. x^4. Terms with even exponents have endpoints at positive y ∞ for positive and negative x infinity. 
2. -2x^2. The negative sign simply reflects x^2 over the x-axis, so the end behavior extends to negative y ∞ for positive and negative x ∞. The scalar, 2, does not impact this.
3. -x^5. Terms with odd exponents have endpoints in opposite directions, i.e. positive y ∞ for positive x ∞ and negative y ∞ for negative x ∞. Because of the negative sign, this specific graph is flipped over the x-axis and results in flipped directions for endpoints.
4. -x^2. Again, this would originally have both endpoints at positive y ∞ for positive and negative x ∞, but because of the negative sign, it is flipped to point towards negative y ∞.
3 0
3 years ago
What is the approximate value of point Y?<br><br> second picture is the answer's
Doss [256]
<h2>Hello!</h2>

The answer is: A. 2π

<h2>Why?</h2>

First,  in order to make it easier, let's convert the numbers into entire or decimal numbers.

A=2\pi=6.28\\B=2\sqrt{12}=6.92\\C=\sqrt{8}=2.82\\D=5.4

So, ordering it:

C, D, A, B

W=C=2.82\\X=D=5.4\\Y=A=6.28\\Z=B=6.92

So, Y=A=6.28

Have a nice day!

6 0
3 years ago
What is the area of the shaded region on the graph shown?
Sindrei [870]

Answer:

As Doris Day said: Good morning to you

Answer 27/2

Step-by-step explanation:

f(x)=-x^3+5x\\F(x)=-\dfrac{x^4}{4} +\dfrac{5x^2}{2} \\F(2)=\dfrac{-16}{4}+\dfrac{20}{2}  =6\\\\F(-1)=\dfrac{-1}{4} +\frac{5}{2} =\dfrac{9}{4} \\g(x)=\dfrac{3x^2}{2}+\dfrac{x}{2}-5\\\\G(x)=\dfrac{x^3}{2}   +x^2-5x\\\\G(2)=4+1-10=-5\\\\G(-1)=\dfrac{-1}{2} +\dfrac{1}{4} +5=\dfrac{19}{4} \\\\\int\limits^2_{-1} {(f(x)-g(x))} \, dx =F(2)-G(2)-(F(-1)-G(-1))\\\\=11+\dfrac{5}{2} =\dfrac{27}{2}

5 0
3 years ago
The Pet Palace is replacing its dog training arena with a new arena with dimensions that
babunello [35]
(A) 450 ft squared.

First, calculate the old arena's dimensions. 
10 x 15 = 150.

Calculate the new arena's dimensions.
20 x 30 = 600.

Now subtract 150 from 600.
600 - 150 = 450. 

Hope I helped!
6 0
3 years ago
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