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UkoKoshka [18]
3 years ago
11

Need help with geometry

Mathematics
1 answer:
ra1l [238]3 years ago
3 0
The answer is x=3 because abt+tbc=abc
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I see 12 t<span>riangles!!!!</span>
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Kevin wants to buy an area rug for his living room. He would like the area rug to be no smaller that 48 square feet and no bigge
mariarad [96]

Answer:

8-10 feet

Step-by-step explanation:

If the length of the carpet is two more than the width, the width can be expressed as x and the length can be expressed as x+2. This means that the area(x^2+2x) must be greater than 48 but no less than 80.

Now we can solve for both the maximum and minimum cases:

x^2+2x=48, x^2+2x-48=0, now we can factor, (x+8)(x-6)=0, and now we can use the Zero Product Property to find x=-8;x=6. Since we cant have negative width, x at least has to be equal to 6.

x^2+2x=80,x^2+2x-80=0, now we can factor, (x+10)(x-8), and now using the Zero Product Property to find x=-10;x=8, and since it must be positive, at most x can equal 8.

Now since the length is two more than the width, x, you add two to both of these values and get a range of 8-10 feet.

3 0
4 years ago
What does 7/8 × 9/10 equal
Hoochie [10]
(7/8)*(9/10)=7*9/(8*10)=63/80
7 0
3 years ago
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Which collection of three side lengths will not form a triangle
Schach [20]
To construct a triangle, the sum of any 2 sides of the triangle should be greater than the third side of the triangle.
lets calculate the sums of all the given choices to find out which three lengths given do not form a triangle.

A.
 6,10,18
6 + 10 = 16 
16 is smaller than the third side-18
Therefore these 3 lengths do not form a triangle

B.10,12,15
10 + 12 = 22                  15+12 = 27                         15 + 10 = 25
22>15 (3rd side)            27>10 (3rd side)                    25>12 (3rd side)
In this triangle, sum of all the possible pairs of sides are greater than the third side therefore these lengths can form a triangle 

C.10,15,6
10 + 15 = 25                      15 + 6 = 21                              10+6 = 16
25 >  6                                 21>10                                      16>15
in this too, sum of all the possible pairs of sides are greater than the third side. These lengths can be used to form a triangle

D.10,18 ,12
10 + 18 = 28                      18 + 12 = 30                             10 +12 = 22
28> 12                                    30>10                                      22> 18
Therefore these lengths can also be used to form a triangle

correct answer is 6,10 and 18 these cannot form a triangle
8 0
3 years ago
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