Answer:
Part 1) x-intercept is -4;y-intercept is 8
Part 2) x-intercept is 16; y-intercept is 20
Part 3) 
Part 4)
Part a) 
Part b) The graph in the attached figure
Step-by-step explanation:
Part 1) Find the x- and y-intercept of the line
we have

we know that
The x-intercept is the value of x when the value of y is equal to zero
so
For y=0



The y-intercept is the value of y when the value of x is equal to zero
so
For x=0



therefore
x-intercept is -4;y-intercept is 8
Part 2) Find the x- and y-intercept of the line
we have

we know that
The x-intercept is the value of x when the value of y is equal to zero
so
For y=0



The y-intercept is the value of y when the value of x is equal to zero
so
For x=0

therefore
x-intercept is 16; y-intercept is 20
Part 3) Write y=-(1/6)x+4 in standard form using integers.
we know that
The equation of a line in standard form is equal to

where
A is a positive integer
B and C are integers
we have

Multiply both sides by 6 to remove the fraction

Adds x both sides

Part 4) The grocery store sells kumquats for $4.75 a pound and Asian pears for $2.25 a pound.
Part a) Write an equation in standard form for the weights of kumquats k and Asian pears p that a customer could buy with $22
Part b) Graph the equation
Part a)
Let
k -----> the number of pounds of kumquats bought
p ----> the number of pounds of Asian pears bough
we know that
The number of pounds of kumquats bought (k) multiplied by it cost of $4.75 a pound plus the number of pounds of Asian pears bough (p) multiplied by it cost of $2.25 a pound must be equal to $22
so

Part b) Graph the equation
To graph the line find out the intercepts
Let
k the first coordinate of the point
p the second coordinate of the point
The k-intercept is the value of k when the value of p is equal to zero
so
For p=0



so
The k-intercept is the point (4.63,0)
The p-intercept is the value of p when the value of k is equal to zero
so
For k=0



so
The k-intercept is the point (0,9.78)
using a graphing tool
Plot the intercepts and join the points to graph the line
see the attached figure
Remember that the weight cannot be a negative number