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STALIN [3.7K]
3 years ago
11

Jason has two bags with 6 tiles each. The tiles in each bag are shown below: Make 6 squares. The squares are numbered sequential

ly from 1 to 6. Without looking, Jason draws a tile from the first bag and then a tile from the second bag. What is the probability of Jason drawing the tile numbered 5 from the first bag and an odd tile from the second bag?
Mathematics
1 answer:
11111nata11111 [884]3 years ago
6 0
1/5 and 1/2 so 20% and 50%
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The endpoints of a diameter of a circle are A(3,1) and B(9,9). Find the area of the circle in terms of pie
andrey2020 [161]

Answer:

The answer is 25\pi units squared.

Step-by-step explanation:

If we find the diameter, we can find the radius by halving the diameter.

We can find the diameter by using the endpoints of the diameter.

The distance formula will give us the length between (3,1) and (9,9).

The distance formula is \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}.

The distance between the x's is 9-3=6.

The distance between the y's is 9-1=8.

The distance between the points is given by \sqrt{6^2+8^2}=\sqrt{36+64}=\sqrt{100}=10.

The radius is therefore \frac{10}{2}=5.

We are asked to find the area of this circle.

The formula for finding the area of a circle is \pi r^2.

Since the radius is 5, then the area in terms of \pi,(pi), is \pi (5)^2=\pi (25).

The answer is 25\pi units squared.

4 0
3 years ago
Simplify
frosja888 [35]
Just do this :
-1 + 30 - 5y
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6 0
3 years ago
A clinical trial tests a method designed to increase the probability of conceiving a girl. In the study 340 babies were​ born, a
Bas_tet [7]

Answer:

The 99% confidence interval estimate of the percentage of girls born is (0.8, 0.9).

b)Yes, the proportion of girls is significantly different from 0.5.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence interval 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

Z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

In the study 340 babies were​ born, and 289 of them were girls. This means that n = 340, \pi = \frac{289}{340} = 0.85

Use the sample data to construct a 99​% confidence interval estimate of the percentage of girls born.

So \alpha = 0.01, z is the value of Z that has a pvalue of 1 - \frac{0.01}{2} = 0.995, so z = 2.575.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{340}} = 0.85 - 2.575\sqrt{\frac{0.85*0.15}{400}} = 0.80

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{340}} = 0.85 + 2.575\sqrt{\frac{0.85*0.15}{400}} = 0.90

The 99% confidence interval estimate of the percentage of girls born is (0.8, 0.9).

Does the method appear to be ​effective?

b)Yes, the proportion of girls is significantly different from 0.5.

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x  \geqslant  -  \frac{1}{ {12x}^{2} + 12x }
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Answer: It was the third answer. C.

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