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Sonja [21]
3 years ago
14

-8-8(6n+1) solve using distributive property

Mathematics
1 answer:
cupoosta [38]3 years ago
8 0

Answer:

-48n-16

Step-by-step explanation:

-8 -8(6n +1)

= -8 + -48n + -8

= (-48n) + (-8 + -8)

= -48n + -16

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Which of the following is NOT a lifestyle factor that affects physical fitness?
jolli1 [7]

Answer:

option D clothing

Step-by-step explanation:

Physical fitness is defined as the ability of one to carry out his task without fatigue. This includes muscle strength, flexibility, body composition, cardio respiratory endurance.

Hence we find that clothing has nothing to do with the above things in any way.

Work burns calories and related to physical fitness similarly chores and exercise also

So option D clothing is right answer.

4 0
3 years ago
Read 2 more answers
Slope passing through the points of (3,-3) and (2,-5)
umka2103 [35]

Answer:

Use the slope formula (y2-y1)÷(x2-x1)

Step-by-step explanation:

(-5-(-3))÷2-3

= (-2.5,-1)

4 0
3 years ago
Why do whole numbers with an exponent get bigger while fractions with an exponent get smaller.
ohaa [14]

Raising a whole number to a power means: 

             Take (a number of things) a number of times, and then possibly
             take that big number of things a number of times again.

Raising a fraction to an exponent means: 

             Take a piece of (a piece of one thing), and then possibly
              take just a piece of that smaller piece.


8 0
3 years ago
analyze the diagram below and complete the instructions that follow . find the value of z. A.11 B.32 C.50 D.68​
masha68 [24]

Answer:

50

Step-by-step explanation:

x = √30² - 18² = √576 = 24

tan A = 18/24 = 3/4

∠A = ∠B

tan B = tan A = 24 / y = 3 / 4

y = (24 x 4) / 3 = 32

Z = y + 18 = 32 + 18 = 50

3 0
3 years ago
For fun question
ZanzabumX [31]
Consider the function f(x)=x^{1/3}, which has derivative f'(x)=\dfrac13x^{-2/3}.

The linear approximation of f(x) for some value x within a neighborhood of x=c is given by

f(x)\approx f'(c)(x-c)+f(c)

Let c=64. Then (63.97)^{1/3} can be estimated to be

f(63.97)\approxf'(64)(63.97-64)+f(64)
\sqrt[3]{63.97}\approx4-\dfrac{0.03}{48}=3.999375

Since f'(x)>0 for x>0, it follows that f(x) must be strictly increasing over that part of its domain, which means the linear approximation lies strictly above the function f(x). This means the estimated value is an overestimation.

Indeed, the actual value is closer to the number 3.999374902...
4 0
3 years ago
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