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9966 [12]
3 years ago
6

A company is testing and comparing two lightbulb designs. The box plots show the number of hours that each lightbulb design last

s before burning out. Which statement is best supported by the information in the plots?

Mathematics
2 answers:
Marrrta [24]3 years ago
7 0

Answer:

Design B bulbs will likely last longer than design A bulbs

Step-by-step explanation:

The B box  part spans higher numbers than the A box  and  the median of B bulbs is higher than median of the A bulbs.

kkurt [141]3 years ago
5 0

i am pretty sure that it is one of them from the right(the ones that start with B)

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james has a board that is 3/4 long he wants to cut the board into 1/8 pieces how many pieces can james cut from the board write
Vilka [71]
The answer can be 6/1 or just 6. And visit www.caculatorsoup.com
4 0
3 years ago
Pls help!!!! ahhhhhhhhhhhhhhhhhhhhhhhhhhhhh
sp2606 [1]

Answer:

1:2

Step-by-step 1:2explanation:

it doesnt say anything about colors. so how many dots? how many stripes? 2 and 4. Ratio: 2:4. Ratios can be fractions: 2/4. What does 2/4 simplify to? 1/2 That means for every 1 dot rectangle there are 2 stripe rectangle. Ratio : 1:2 or 1 to 2 or 1/2

5 0
3 years ago
When solving for the value x in the equation 4(x-1) +6= 18, aaron wrote the following lines on the board:
iren [92.7K]

Answer:

The Distributive Property.

Step-by-step explanation:

4(x - 1) = 12

When distributing out the 4, it must go to all the terms within the brackets like this:

4x - 4 = 12.

4x = 16

x = 4.

8 0
2 years ago
A certain substance doubles its volume every minute at 9 AM a small amount is placed in a container ,at 10 AM the container was
Y_Kistochka [10]

Answer:

the container is 1/4 full at 9:58 AM

Step-by-step explanation:

since the volume doubles every minute , the formula for calculating the volume V at any time t is

V(t)=V₀*2^-t , where t is in minutes back from 10 AM and V₀= container volume

thus for t=1 min (9:59 AM) the volume is V₁=V₀/2 (half of the initial one) , for t=2 (9:58 AM) is V₂=V₁/2=V₀/4  ...

therefore when the container is 1/4 full the volume is V=V₀/4 , thus replacing in the equation we obtain

V=V₀*2^-t

V₀/4 = V₀*2^-t

1/4 = 2^-t

appling logarithms

ln (1/4) = -t* ln 2

t = - ln (1/4)/ln 2 = ln 4 /ln 2 = 2*ln 2 / ln 2 = 2

thus t=2 min before 10 AM → 9:58 AM

therefore the container is 1/4 full at 9:58 AM

8 0
2 years ago
Need to keep cell bill under 60.,monthly charge is 30. And texts are 0.05 each. Write an inequality to represent the # of texts
nignag [31]

Answer:

30 + 0.05x < 60

The number of texts she can have is less than 600.

Step-by-step explanation:

Total monthly charge

30 + 0.05 for each text.

So, for x tests, the charge is:

C(x) = 30 + 0.05x

Write an inequality to represent the # of texts she can have?

It has to be under 60, so:

C(x) < 60

30 + 0.05x < 60

The solution is:

0.05x < 30

x < \frac{30}{0.05}

x < 600

The number of texts she can have is less than 600.

5 0
2 years ago
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