Question

30 points! Need Help Asap!!

Answer 1

Regarding the frequency table, it is found that:

1. The sum of the frequencies is of 28.

2. The probabilities of each outcome are given as follows: P(0) = 0.21, P(1) = 0.36, P(2) = 0.25, P(3) = 0.18.

3. Considering the probabilities, the table is completed as follows: 0.21 | 0.36 | 0.25 | 0.18.

Probability

A probability of an outcome in an experiment is given by the division of the absolute frequency of the outcome by the sum of all the absolute frequencies.

The absolute frequencies are given as follows:

6, 10, 7 and 5.

Then the probabilities are calculated as follows:

• P(0) = 6/28 = 0.21.

• P(1) = 10/28 = 0.36.

• P(2) = 7/28 = 0.25.

• P(3) = 5/28 = 0.18.

For each outcome, the absolute frequency of the outcome was divided by the sum of these absolute frequencies.

For item 3, the table is completed with these probabilities, hence:

0.21 | 0.36 | 0.25 | 0.18.

A similar problem, also involving probabilities, is presented at brainly.com/question/14398287

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