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Paladinen [302]
3 years ago
10

Letv⃗ 1=⎡⎣⎢012⎤⎦⎥,v⃗ 2=⎡⎣⎢1−20⎤⎦⎥,v⃗ 3=⎡⎣⎢30−1⎤⎦⎥be eigenvectors of the matrix A which correspond to the eigenvalues λ1=−3, λ2=2

, and λ3=3, respectively, and letx⃗ =⎡⎣⎢−433⎤⎦⎥.Express x⃗ as a linear combination of v⃗ 1, v⃗ 2, and v⃗ 3, and find Ax⃗ .x⃗ = -3 v⃗ 1+ 2 v⃗ 2+ 3 v⃗ 3.Ax⃗ = ⎡⎣⎢⎢⎢⎢⎢⎢ ⎤⎦⎥⎥⎥⎥⎥⎥
Mathematics
1 answer:
dem82 [27]3 years ago
6 0
What is this????????????????????
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Let's follow the transformations that happen to A, to get to A' and A''.

Point A is at (-5, -2)

It moves to (-5, 2) which is where A' is located. Note the x coordinate stays the same while the y coordinate flips from negative to positive. This must mean we applied a reflection over the x axis.

That rule in general is (x, y) \rightarrow (x,-y)

------------------------------------

Now compare A'(-5,2) and A''(1,4). We can shift A' 6 units to the right and then 2 units up so we move from A' to A''.

Algebraically this is stated as (x,y) \rightarrow (x+6, y+2)

Whatever the x coordinate is, add 6 to it. For the y coordinate, we add on 2.

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The same applies to moving C' to C''

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In summary, we started off by reflecting over the x axis. Then we applied the translation rule of "shift to the right 6 units, shift up 2 units".

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