To solve this problem you must apply the proccedure shown below:
1. You have the following expression given in the problem above:
![\sqrt[3]{216 x^{27} }](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B216%20x%5E%7B27%7D%20%7D%20)
2. Rewriting the expression we have:
![\sqrt[3]{6^3 x^{27} }](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B6%5E3%20x%5E%7B27%7D%20%7D%20)
3. You have that

and the exponent

are divisible by index

. Therefore, you have:
![\sqrt[3]{216 x^{27} } =6 x^{9}](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B216%20x%5E%7B27%7D%20%7D%20%3D6%20x%5E%7B9%7D%20)
Therefore, as you can see,
the answer is the option, which is:
V=12, comment if u need an explanation
Answer:
78
Step-by-step explanation:
Smallest square: 1
Small Square: 2, Area of 4
Mid Square: 3, Area of 9
Mid White Square: 5, Area of 25
Big Square: 8, Area of 64
1 + 4 + 9 + 64 = 78
<h2><u>Diagram</u><u>:</u><u>-</u></h2>

<h3><u>Required Answer</u><u>:</u><u>-</u></h3>
The diagonals of the Rhombus= d1 & d2=6cm and 8cm
Let the Side=a
As we know that in a Rhombus











<h2>_____________</h2><h3>Again </h3>
we know that in a Rhombus





Perimeter of the rectangle is 20cm.
Answer:
16 
Step-by-step explanation:
multiply 4 by 4