Perimeter of the ΔJKL is 48 cm
Solution:
Given
.
RS = 8 cm and JK = 12 cm
Perimeter of
= 32 cm
Let us find the perimeter of
.
<u>Property of similarity triangles:</u>
If two triangles are similar, then the ratio of their perimeters is equal to the ratio of their corresponding sides.


Do cross multiplication.


Divide both sides of the equation by 8.

Hence perimeter of the ΔJKL is 48 cm.
If you are looking for the y intercept it is (0,-5) or -5
Answer:
x=20
Step-by-step explanation:
we know the straight angle theorum...
3x+80+2x=180
5x=100
x=20
Area divided by pi(2.25 squared/pi), which is 1.611