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Aloiza [94]
3 years ago
12

A data set can have more than one median? True False​

Mathematics
2 answers:
MaRussiya [10]3 years ago
8 0

Answer:

False

Step-by-step explanation:

Colt1911 [192]3 years ago
3 0
The median and mean can only have one value for a given data set so the answer is false
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Estelle drew two parallel lines PQ and R0S intersected by a transversal KL, as shown below: Which theorem could Estelle use to s
Sophie [7]
Angle KMQ and angle RNL are  on apposite sides of the transversal and between above and below (exterior to) the parallel lines, so they are alternate exterior angles.  Theorem - Alternate exterior angles formed by parallel lines and a transversal have the same measure.

8 0
2 years ago
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Write the ratio for sin A.<br> A<br> 17<br> 15<br> с<br> B<br> sin A=
Firlakuza [10]

Answer:

0.292371705 if A=17

0.258819045 if A=15

Step-by-step explanation:

What are all the other options i dont understand

6 0
3 years ago
PLEASE HELP
liq [111]
--------------------------------------------
Question
--------------------------------------------
3 \times 1000 + 6 \times 100 + 1 \times 10 + 2 \times \frac{1}{10}  + 1 \times  \frac{1}{1,000}

--------------------------------------------
Convert the fractions to decimals
--------------------------------------------
3 \times 1000 + 6 \times 100 + 1 \times 10 + 2 \times 0.1  + 1 \times  0.001

--------------------------------------------
Evaluate each term
--------------------------------------------
3000 + 600 + 10 + 0.2 + 0.001

--------------------------------------------
Add them up
--------------------------------------------
3610.201

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Answer : 3610.201
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3 0
3 years ago
The length of a rectangle is 4 less than three times it’s width. The perimeter is 72 feet. Find the dimensions of a rectangle
ratelena [41]

Answer:

Step-by-step explanation:

so let’s say x is the length.  Then the width will be 3x-4.  You add them together and multiply by two.  The perimeter is 72 so the equation equala 72.

Equation:

(x+3x-4)*2=72

(4x-4)*2=72

8x-8=72

8x=80

x=10

length:10

width:26

6 0
3 years ago
Which step is the same in the construction of parallel lines and the construction of a perpendicular line through a point on the
madam [21]

Answer:

D.Place the compass on a point on the original line.

Complete Question:

A.Create only one arc that intersects the original line.

B.Create two arcs that intersect the original line.

C.Place the compass on a point off the original line.

D.Place the compass on a point on the original line.

Step-by-step explanation:

* Lets revise the steps of constructing parallel lines and a perpendicular line through a point on the line

<em># Contracting parallel lines</em>

- Given: Line AB and point P not on AB

1. Draw a slant line through point P and intersects AB at point C, this line is the transversal of the parallel lines

2.<u> Place the pin of the compass at point C</u> and draw an arc intersects AB at D and CP at E

3. Without changing the distance of the compass put the pin of the compass on point P and draw an arc intersects CP at point Q

4. Use the compass to measure the distance from D to E and place the pin of the compass at point Q and draw an arc intersects the arc from P to CP at point U

5. Join P and U by a line this line is parallel to AB

<em># Constructing a perpendicular line through a point on the line</em>

- Given line AB and point P lies on it

1. <u>Place your compass pin at P </u>and draw an arc of any size below AB that crosses the line twice at points C and D

2. Stretch the compass to a larger distance

3.<u> </u>Place the compass pin on point C<u> </u>and draw a small arc above the line

4. Without changing the distance of the compass place the compass pin on point D and draw another arc intersects the arc from C at point E

5. Using a straightedge, join P and E where PE is perpendicular to AB

*<em> Lets find the same steps in the constructions</em>

∵ In first construction we put the pin of the compass at point C which  lies in the original line AB

∵ In second construction we put the pin of the compass at point P which lies in the original line AB

∴ The common step is:  <em><u>"Place the compass on a point on the original line"</u></em>

6 0
3 years ago
Read 2 more answers
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