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Aloiza [94]
3 years ago
12

A data set can have more than one median? True False​

Mathematics
2 answers:
MaRussiya [10]3 years ago
8 0

Answer:

False

Step-by-step explanation:

Colt1911 [192]3 years ago
3 0
The median and mean can only have one value for a given data set so the answer is false
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WILL GIVE BRAINLIEST ! ANSWER ASAP!
bazaltina [42]

Answer:

x=17

Step-by-step explanation:

5 0
2 years ago
Help me please I need this done by tomorrow!!!!
Reptile [31]
12) 12, 8

12 - 8 = 4

12 + 8 = 20

Answer: 4 < x <span>< 20

13) 11, 3

11 - 3 = 8

11 + 3 = 14

Answer: 8 </span>< x <span>< 14

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3 0
3 years ago
There are 3 red marbles, 5 green marbles, and 2 blue marbles in a jar. Event A is defined as drawing a red marble from the jar o
Anastaziya [24]

P(B/A) is \frac{5}{9} in the simplest form

Step-by-step explanation:

Let us explain how to solve the problem

  • P(B|A) is called the "Conditional Probability" of B given A
  • Conditional probability is the probability of one event occurring with some relationship to one or more other events that means event A has already happened, now what is the chance of event B
  • The formula for conditional probability is P(B|A) = P(A and B)/P(A), where P(A and B) is P(A) . P(B given A occurred)

∵ There are 3 red marbles, 5 green marbles, and 2 blue

   marbles in the jar

∴ The total number of the marbles in the jar = 3 + 5 + 2 = 10

∵ Two marbles are drawn from the bag, one after the other without

   replacement

- That means red is already occurred when green is happened,

  so it is a "Conditional Probability" of green given red

  P(B/A) = P(A and B)/P(A)

∵ Event A is defined as drawing a red marble from the jar on

   the first draw

∴ P(A) = P(red)

∵ P(red) = \frac{3}{10}

∴ P(A) = \frac{3}{10}

∵ Event B is defined as drawing a green marble on the second draw

∴ P(B) = P(green)

- The number of marbles after the red is chosen is 9

∵ P(green) = \frac{5}{9}

∴ P(B) = \frac{5}{9}

- Find P( A and B)

∴ P(A and B) = ( \frac{3}{10} ) . ( \frac{5}{9} )

∴ P(A and B) = \frac{15}{90}

- Simplify the fraction by divide up and down by 15

∴ P(A and B) = \frac{1}{6}

∵ P(B|A) = P(A and B)/P(A)

- Substitute the values of P(A and B) and P(A) in the rule above

∴ P(B/A) = \frac{\frac{1}{6}}{\frac{3}{10}}

- Simplify the fraction

∵ \frac{1}{6} ÷ \frac{3}{10} = \frac{1}{6} × \frac{10}{3} = \frac{10}{18}

- Divide up and down by 2

∴ P(B/A) = \frac{5}{9}

P(B/A) is \frac{5}{9} in the simplest form

Learn more:

You can learn more about probability in brainly.com/question/10744457

#LearnwithBrainly

7 0
3 years ago
Read 2 more answers
Ana purchased a used car with 35,500 miles on it. After 4 years of driving, the car has 90,300 miles on it
Aleksandr-060686 [28]
Your answer is this
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Because
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5 0
3 years ago
The heights of North American women are normally distributed with a mean of 64 inches and a standard deviation of 2inches.a. Wha
Charra [1.4K]

Answer:

a)P(X>66)=P(Z>1)=1-P(Z

b)P(\bar X >66)=P(Z>2)=1-P(Z

c) P(\bar X >66)=P(Z>10)=1-P(Z

Step-by-step explanation:

1) Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

2) Part a

Let X the random variable that represent the heights of a population, and for this case we know the distribution for X is given by:

X \sim N(64,2)  

Where \mu=64 and \sigma=2

We are interested on this probability

P(X>66)

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X>66)=P(\frac{X-\mu}{\sigma}>\frac{66-\mu}{\sigma})=P(Z>\frac{66-64}{2})=P(Z>1)

And we can find this probability on this way:

P(Z>1)=1-P(Z

3) Part b

From the central limit theorem we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

P(\bar X >66)=P(Z>\frac{66-64}{\frac{2}{\sqrt{4}}}=2)

And using a calculator, excel or the normal standard table we have that:

P(Z>2)=1-P(Z

4) Part c

P(\bar X >66)=P(Z>\frac{66-64}{\frac{2}{\sqrt{100}}}=10)

And using a calculator, excel or the normal standard table we have that:

P(Z>10)=1-P(Z

3 0
3 years ago
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