Question

A rectangular garden is 5 ft longer than it is wide. Its area is 300 ft2. What are its dimensions?​

Answer 1

Step-by-step explanation:

the area of a rectangle is

length × width = 300 ft²

length = width + 5

(width + 5) × width = 300

width² + 5×width = 300

width² + 5×width - 300 = 0

the general solution to such a quadratic equation is

width = (-b ± sqrt(b² - 4ac))/(2a)

in our case

a = 1

b = 5

c = -300

width = (-5 ± sqrt(5² - 4×1×-300))/(2×1) =

= (-5 ± sqrt(25 + 1200))/2 =

= (-5 ± sqrt(1225))/2 = (-5 ± 35)/2

width1 = (-5 + 35)/2 = 30/2 = 15 ft

width2 = (-5 - 35)/2 = -40/2 = -20 ft

negative lengths for an actual object don't make sense, so width = 15 ft is our solution.

length = width + 5 = 15 + 5 = 20 ft

Answer 2

Answer:

width=x

length=5x

area= 300ft2

area=lxb

300=5x(x)

300=5x^2

x^2=60

x=7.74

7.74(5)=38.7

dimensions are 38.7ft by 7.74 ft

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