The volume of aggregate that she needs to build the patio is 13.18 ft^3
<h3>How many cubic feet of aggregate would she need to build the walkway?</h3>
We know that the backyard is 14ft long, 6 feet wide and 4 inches deep.
Rememeber that:
1ft = 12 in
Then:
4 in = (4/12) ft = (1/3) ft
Then the volume of the backyard is:
V = (14ft)*(6ft)*(1/3 ft) = 28ft^3
Now we know that we have a mix of 4 parts aggregate to 4.5 parts loose cement that need to fill these 28 cubic feet.
Note that:
4 + 4.5 = 8.5
How many times we have 8.5 in 28?
28/8.5 = 3.294
Now for each of these we have 4 parts of aggregate, then the volume of aggregate that we need is:
4*3.294 ft^3 = 13.18 ft^3
The volume of aggregate that she needs to build the patio is 13.18 ft^3
If you want to learn more about volumes:
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The coordinate for the point M is (51/6, 13/6) if the point M on a segment with endpoints X (1, -2) and Y (10, 3) partitions the segment in a 5:1 ratio.
<h3>How to explain the information?</h3>
We have a line segment: XY with end coordinates X(1, -2) and Y(10, 3)
The coordinate for the point M:
x = (1+50)/6 = 51/6
y = (-2+15)/6 = 13/6
Thus, the coordinate for the point M is (51/6, 13/6) if the point M on a segment with endpoints X (1, -2) and Y (10, 3) partitions the segment in a 5:1 ratio.
Learn more about the segment here:
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X = 4 and y = 4 square root 2
In Perpendicular product of slope is -1 so slope of y=2x-4 is 2 and 2*m=-1 m= -1/2 so y= -1/2x -4
Answer: y= 12x +40
Step-by-step explanation:
