Answer:
What is the probability that a randomly selected family owns a cat? 34%
What is the conditional probability that a randomly selected family doesn't own a dog given that it owns a cat? 82.4%
Step-by-step explanation: We can use a Venn (attached) diagram to describe this situation:
Imagine a community of 100 families (we can assum a number, because in the end, it does not matter)
So, 30% of the families own a dog = .30*100 = 30
20% of the families that own a dog also own a cat = 0.2*30 = 6
34% of all the families own a cat = 0.34*100 = 34
Dogs and cats: 6
Only dogs: 30 - 6 = 24
Only cats: 34 - 6 = 28
Not cat and dogs: 24+6+28 = 58; 100 - 58 = 42
What is the probability that a randomly selected family owns a cat?
34/100 = 34%
What is the conditional probability that a randomly selected family doesn't own a dog given that it owns a cat?
A = doesn't own a dog
B = owns a cat
P(A|B) = P(A∩B)/P(B) = 28/34 = 82.4%
Answer:
2 units up
Step-by-step explanation:
You're just taking the entire graph of cos(x) and then adding 2 so it moves everything up. If you added 2 to x BEFORE taking the cosine
(like y = cos (x+2) ), then you would shift it left 2. Adding and subtracting from the x moves everything left or right. Adding or subtracting at the end just moves it up and down.
Answer:
y=-5x-13
Step-by-step explanation:
use y-y1=m(x-x1)
y+8=-5(x+1)
y+8=-5x-5
subtract 8 from both sides
y=-5x-13
Answer:
For a pair of randomly selected in- and out-of-state students, the sum of their tuition typically varies from the mean of $6,348.75 by about $1,508.48.
Step-by-step explanation:
Given

Required
Interpret the standard deviations
In statistic, standard deviation is a measure of how the given data lies away (or varies) from the mean.
This implies that:
For the in-state students, the standard deviation measures how the sum of their tuition varies from 6348.75
For the out-state students, the standard deviation measures how the sum of their tuition varies from 1508