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Ivanshal [37]
1 year ago
4

Find A (please help)

Mathematics
1 answer:
Zarrin [17]1 year ago
3 0

Answer: Solve 5x=(2x+3)

Step-by-step explanation:

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use the data set shown below to complete the sentence. 3, 3, 4, 5, 5, 9 the mean is ___________ the median. 1.less then 2.equal
kotegsom [21]
3. Greater than

Median is the middle number of the data set. But in this senario, there are 2 numbers in the middle. So you can take 4+5/2=4.5

To find Mean, you can must take all the numbers in the data set divided by the number of data collected.

In this case, (3+3+4+5+5+9)÷6

You will find that the mean is greater than the median.
5 0
4 years ago
Read 2 more answers
Find the range of ƒ(x) = 3x – 5 for the domain {–1.5, 2, 4}.
Effectus [21]

Answer:

{-9.5, 1,7}

Step-by-step explanation:

For y =f(x)

domain is list of all values of x and range is list of all values of y

Given

ƒ(x) = 3x – 5

domain = {–1.5, 2, 4}.

thus,

range will be value of f(x)

when x = -1.5

x = 2 and x = 4

Thus,

for x = -1.5

ƒ(x) = 3*-1.5 – 5 = -4.5 - 5 = -9.5

\

for x = 2

ƒ(x) = 3*2– 5 = 6 - 5 = 1

for x = 4

ƒ(x) = 3*4– 5 = 12 - 5 = 7

thus,

range of ƒ(x) = 3x – 5 is {-9.5, 1,7}

7 0
3 years ago
Write an equation and solve for the value of x stare the reason for your equation
Troyanec [42]

Remember that the total of the angles always equals 180 degrees

4x + 2 + 8 + 6x + 30 = 180

Now solve

4x + 2 - 2 + 8 + 6x + 30 = 180 - 2

4x + 8 - 8 + 6x + 30 = 178 - 8

4x + 6x + 30 - 30 = 170 - 30

4x + 6x = 140

10x = 140

10x ÷ 10 = 140 ÷ 10

x = 14


Now that we know what x is we can fill in the blanks

4(14) + 2

58 + 2

58

Angle O is 58 degrees


8 + 6(14)

8 + 84

92

Angle R is 92 degrees


To check we can add them all up

30 + 58 + 92 = 180


x = 14

4 0
3 years ago
What's is 25/6 as and importers fraction
Korvikt [17]
Esto meda la respuesta

5 0
4 years ago
An agricultural sprinkler distributes water in a circular pattern of radius 100 ft. It supplies water to a depth of e^-r feet pe
Elan Coil [88]

A circle of radius R ft has area \pi R^2 sq ft. For any fixed R, water will reach a depth of e^{-R} ft. You can think of the total volume of water supplied within a radius R of the sprinkler as the volume of the "cylinder" with "height" given by e^{-r} for some 0.

This volume is

\displaystyle\int_0^{2\pi}\int_0^Rre^{-r}\,\mathrm dr\,\mathrm d\theta=2\pi(1-e^{-R}(R+1))

cu ft.

3 0
3 years ago
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