The length of the rectangle is 9 and the width of the rectangle is 5
<h3>Perimeter of a Rectangle</h3>
From the question, we are to determine the length and width of the rectangle
From the given information,
"<em>The width of a rectangle is 2 meters more than one third the length</em>"
If w represents the width
and l represents the length
Then, we can write that
w = 1/3(l) + 2 ---------- (1)
Also, from the given information
"<em>The perimeter is 28 meters</em>"
That is,
28 = 2(l + w) ---------- (2)
From equation (1)
w = 1/3(l) + 2
w - 2 = 1/3(l)
3(w - 2) = l
l = 3(w - 2)
l = 3w - 6 ---------- (3)
Substitute into equation (2)
28 = 2(l + w)
28 = 2(3w - 6 + w)
28 = 6w - 12 + 2w
28 + 12 = 6w + 2w
40 = 8w
w = 40/8
w = 5
Substitute into equation (3)
l = 3w - 6
l = 3(5) - 6
l = 15 - 6
l = 9
Hence, the length of the rectangle is 9 and the width of the rectangle is 5
Learn more on Perimeter of rectangle here: brainly.com/question/17297081
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